The ostrich can run 20 miles in 40 minutes.
<u>Solution:</u>
Given that, An ostrich run 6 mile in 12 minutes
We have to find how far he could come in 40 minutes
Now, according to the given information
Ostrich runs 6 miles ⇒ 12 minutes
Then, “n” miles ⇒ 40 minutes
Now, by criss cross multiplication we get,
Hence, the ostrich can run 20 miles in 40 minutes
Answer:
1. D
2. B
3. A
Step-by-step explanation:
Question 1:
The pair of <JKL and <LKM can be referred to as linear pairs. They are two adjacent angles that are formed from the intersecting of two lines.
Question 2:
Given that <KLM = x°
<KML = 50°
<JKL = (2x - 15)°
According to the exterior angle theorem, exterior ∠ JKL = <KLM + KML.
2x - 15 = x + 50
Solve for x
2x - x = 15 + 50
x = 65
Therefore, <KLM = 65°
QUESTION 3:
<JKL = 2x - 15
Plug in the value of x
<JKL = 2(65) - 15
= 130 - 15
<JKL = 115°
Answer:
1/6
Step-by-step explanation:
1/3 + /1/6= 1/2
Because 1.5 is half of 3
<span>Absolute value of -98 is 98
Hope I helped:D </span>
