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Sergeu [11.5K]
3 years ago
5

Let μ denote the true average radioactivity level(picocuries per liter). The value 5 pCi/L is considered thedividing line betwee

n safe and unsafe water. Would you recommend testing H0: μ = 5 vs Ha: μ > 5 or H0: μ =5 vs Ha: μ < 5?
Mathematics
1 answer:
VMariaS [17]3 years ago
7 0

Answer:

H0: μ = 5 versus Ha: μ < 5.

Step-by-step explanation:

Given:

μ = true average radioactivity level(picocuries per liter)

5 pCi/L = dividing line between safe and unsafe water

The recommended test here is to test the null hypothesis, H0: μ = 5 against the alternative hypothesis Ha: μ < 5.

A type I error, is an error where the null hypothesis, H0 is rejected when it is true.

We know type I error can be controlled, so safer option which is to test H0: μ = 5 vs Ha: μ < 5 is recommended.

Here, a type I error involves declaring the water is safe when it is not safe. A test which ensures that this error is highly unlikely is desirable because this is a very serious error. We prefer that the most serious error be a type I error because it can be explicitly controlled.

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What is the solution to log Subscript 3 Baseline (x + 12) = log Subscript 3 Baseline (5 x)
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Answer:

x = 3

Step-by-step explanation:

brainly.com/question/14265179?utm_source=

log3(x + 12)=log3(5x)

since the bases are the same

since they both have log3

log3 cancels out

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2 years ago
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Yes

Step-by-step explanation:

Let p1 represent proportion of women and p2 proportion of men. The null and alternative hypothesis will be as follows

Null hypothesis

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p-value=P(Z≥z)=P(Z≥6.9124)=P(Z≤-6.9124)=0

Since the value of p is less than 0.01, we reject null hypothesis. There’s sufficient evidence that a greater proportion of men is expecting to get a raise

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