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Sergeu [11.5K]
3 years ago
5

Let μ denote the true average radioactivity level(picocuries per liter). The value 5 pCi/L is considered thedividing line betwee

n safe and unsafe water. Would you recommend testing H0: μ = 5 vs Ha: μ > 5 or H0: μ =5 vs Ha: μ < 5?
Mathematics
1 answer:
VMariaS [17]3 years ago
7 0

Answer:

H0: μ = 5 versus Ha: μ < 5.

Step-by-step explanation:

Given:

μ = true average radioactivity level(picocuries per liter)

5 pCi/L = dividing line between safe and unsafe water

The recommended test here is to test the null hypothesis, H0: μ = 5 against the alternative hypothesis Ha: μ < 5.

A type I error, is an error where the null hypothesis, H0 is rejected when it is true.

We know type I error can be controlled, so safer option which is to test H0: μ = 5 vs Ha: μ < 5 is recommended.

Here, a type I error involves declaring the water is safe when it is not safe. A test which ensures that this error is highly unlikely is desirable because this is a very serious error. We prefer that the most serious error be a type I error because it can be explicitly controlled.

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Answer:

7y8.9 ft²

Step-by-step explanation:

Easy way:

Rotate the triangle so that the 12.1 ft side in on the bottom becomes the base.

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3 years ago
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lubasha [3.4K]

Answer:

\large\boxed{A=153\ cm^2}

Step-by-step explanation:

<em>Look at the picture.</em>

We have

square with side length a = 9

trapezoid with base lengths b₁ = 9 and b₂ = 6 and the height length h = 6

right triangle with legs lengths l₁ = 3 + 6 = 9 and l₂ = 6

The formula of an area of a square

A=a^2

Substitute:

A_I=9^2=81\ cm^2

The formula of an area of a trapezoid:

A=\dfrac{b_1+b_2}{2}\cdot h

Substitute:

A_{II}=\dfrac{9+6}{2}\cdot6=\dfrac{15}{2\!\!\!\!\diagup_1}\cdot6\!\!\!\!\diagup^3=(15)(3)=45\ cm^2

The formula of an area of a right triangle:

A=\dfrac{l_1l_2}{2}

Substitute:

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The area of the shape:

A=A_I+A_{II}+A_{III}\\\\A=81+45+27=153\ cm^2

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