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olga nikolaevna [1]
3 years ago
7

What is the answer to this question.. What is 30% of 50?​

Mathematics
2 answers:
shepuryov [24]3 years ago
6 0

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>

<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em><em>.</em>

Digiron [165]3 years ago
3 0

Answer: 15%

Step-by-step explanation: Ok, we have to find what is 30% of 50, all we have to do is...

First, we have to divide the percentage by 100 by using long division.

30 ÷ 100 = 0.3

0.3 * 50 = 15%

I hope this helps!

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Mark the location of 5/3​
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Step-by-step explanation:

5/3 x 9= 45/3= 15

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A mirror has a parabolic surface defined by the equation y =¹⁄₂₄ x² with the vertex (0, 0) at the center of the mirror. When the
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Kisachek [45]

Answer:

\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2}  t^2+1 \ \text{dt} \ = \ 2x^5-8x^2+2x-2

Step-by-step explanation:

\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2}  t^2+1 \ \text{dt} = \ ?

We can use Part I of the Fundamental Theorem of Calculus:

  • \displaystyle\frac{d}{dx} \int\limits^x_a \text{f(t) dt = f(x)}

Since we have two functions as the limits of integration, we can use one of the properties of integrals; the additivity rule.

The Additivity Rule for Integrals states that:

  • \displaystyle\int\limits^b_a \text{f(t) dt} + \int\limits^c_b \text{f(t) dt} = \int\limits^c_a \text{f(t) dt}

We can use this backward and break the integral into two parts. We can use any number for "b", but I will use 0 since it tends to make calculations simpler.

  • \displaystyle \frac{d}{dx} \int\limits^0_{2x} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}

We want the variable to be the top limit of integration, so we can use the Order of Integration Rule to rewrite this.

The Order of Integration Rule states that:

  • \displaystyle\int\limits^b_a \text{f(t) dt}\  = -\int\limits^a_b \text{f(t) dt}

We can use this rule to our advantage by flipping the limits of integration on the first integral and adding a negative sign.

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Now we can take the derivative of the integrals by using the Fundamental Theorem of Calculus.

When taking the derivative of an integral, we can follow this notation:

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For the first term, replace \text{t} with 2x, and apply the chain rule to the function. Do the same for the second term; replace

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Simplify the expression by distributing 2 and 2x inside their respective parentheses.

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Rearrange the terms to be in order from the highest degree to the lowest degree.

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