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SpyIntel [72]
3 years ago
10

9x-20/(x+6)^2 partial fraction decomposition

Mathematics
2 answers:
Kryger [21]3 years ago
3 0

We're looking for a,b such that

\dfrac{9x-20}{(x+6)^2}=\dfrac a{x+6}+\dfrac b{(x+6)^2}

Multiplying both sides by (x+6)^2 gives us

9x-20=a(x+6)+b

Notice that when x=-6, the term involving a vanishes and we're left with

9(-6)-20=b\implies b=-74

Then

9x-20=a(x+6)-74=ax+6a-74\implies a=9

so that

\dfrac{9x-20}{(x+6)^2}=\boxed{\dfrac9{x+6}-\dfrac{74}{(x+6)^2}}

tresset_1 [31]3 years ago
3 0

Answer:

Find the partial fraction decomposition of 6x+8/x2-9x+8

Step-by-step explanation:

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