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QveST [7]
3 years ago
13

PLEASE HELP I NEED HELP ALSO I WILL MARK BRAINLIEST

Mathematics
1 answer:
BartSMP [9]3 years ago
7 0

Answer:

see below

Step-by-step explanation:

Let C be at (0,0)

D is at (7,12)

The slope is

m = (y2-y1)/(x2-x1)

    = (12-0)/(7-0)

   = 12/7

The equation of the line is y = mx+b where m is the slope and b is the y intercept

y = 12/7x +b

The y intercept is (0,0)

y = 12/7x +0

y = 12/7x

The domain is the input values or the values that x can take

X goes from 0 to 7

Domain: {0≤x≤7}

The range is the output values or the values that y can take

y goes from 0 to 12

Range: {0≤y≤12}

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The lines y1 = 2x - 6, y2 = -3x + 4, y3 = -1/2x + 4 intersect to form the sides of a right triangle. Find the perimeter and area
tino4ka555 [31]

The area and perimeter of the triangle is 2/5 square units and (2√10 + 4√5) / 5 units

<h3>Determining the perimeter and area of the triangle giving line equation</h3>

In order to determine the area and perimeter of the lines, we will plot the giving lines, determine the point of intersection and then use the Pythagoras theorem to determine the dimension of the right triangle.

The points of intersection of the line are;

(x₁, y₁) = (- 0.4, 5.2),

(x₂, y₂) = (-0.8, 4.4),

(x₃, y₃) = (0, 4)

Determine the base

b² = c² -a²

b = √(-0.8)² + (4 - 4.4)²

b = 2√5 / 5

Determine the height

h = √((- 0.4) - (- 0.8))² + (5.2 - 4.4)²

height = 2√5 / 5

For the hypotenuse

r = √2 · b

r = 2√10 / 5

<h3>Determine the Perimeter and area</h3>

Perimeter = s1+s2+s3

Perimeter = 2√5 / 5 + 2√5 / 5 + 2√10 / 5

Perimeter = (2√10 + 4√5) / 5 units

<u>For the area</u>

area = 1/2* base * height

A = 0.5 · (2√5 / 5) · (2√5 / 5)

A = 2/5 square units

Hence the area and perimeter of the triangle is 2/5 square units and (2√10 + 4√5) / 5 units

Learn more on area and perimeter of triangles here: brainly.com/question/12010318

#SPJ1

3 0
1 year ago
Between which two numbers will you find -3.25?
Vinil7 [7]

Answer:

A

Step-by-step explanation:

hope it helps

6 0
2 years ago
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Answer:-18

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Step-by-step explanation:

3 0
2 years ago
JL is a common tangent to circles M and K at point J. If angle MLK measures 61ᵒ, what is the length of radius MJ? Round to the n
Sladkaya [172]
3.122

The process to getting this comes in many steps. Firstly, you need to find the angles for JLK and MLJ. To find JLK use the arcsin function using the opposite side and the hypotenuse. 

Arcsin(Opp/Hype) = JLK
Arcsin(.5) = JLK
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This means MLJ = 31 degrees since they add up to 61 degrees. 

Now we need to find the length of LJ, which we can do using the Pythagorean Theorem. 

3^2 + JL^2 = 6^2
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Now that we have the angle of MLJ and the length of JL, we can use the tangent function to find MJ.

Tan(angle) = opp/adj
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7 0
3 years ago
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Will give BRAINIEST
mart [117]

Answer:

10 gallons 12 seconds.

Step-by-step explanation: The arrow is at 10 and pointing where 12 is.

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