Answer:
f(-2) = 0
f(1) = 12
(x^3 - 7x - 6) / (x + 2) = x^2 - 2·x - 3 = (x - 3)(x + 1)
x^3 - 7x - 6 = (x + 2)(x - 3)(x + 1)
Equation: 4x+3=43
Solved: 4x=43-3
4x=40
X=10
Answer:
centre = (1, - 3 )
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
(x - 1)² + (y + 3)² = 73 ← is in standard form
with (h, k ) = (1, - 3 ) ← centre
To solve this problem you must apply the proccedure shown below:
1. You have that the formula for calculate the area of a triangle is:
A=bh/2
Where A is the area of the triangle, b is the base of the triangle and h is the height of the triangle.
bh/2=124
bh=124x2
bh=248
2. The problem asks for the new area of the triangle <span>if its base was half as long and its height was three times as long. Then, you have:
Base=b/2
Height=3h
3. Therefore, when you substitute this into the formula for calculate the area of a triangle, you obtain:
A'=bh/2
(A' is the new area)
A'=(b/2)(3)/2
A'=3bh/4
4. When you substitute bh=248 into </span>A'=3bh/4, you obtain:
<span>
A'=186 units</span>²
<span>
The answer is: </span>186 units²
Step-by-step explanation:
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