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tangare [24]
2 years ago
9

Izzy is Iago's little sister. She is counting her coins. Izzy finds that she has three more quarters ($0.25) than she has dimes

($0.10), twice as many nickels ($0.05) as she has dimes, and four times as many pennies ($0.01) as she has dimes. With a total of $7.61 in coins, how many coins of each type does Izzy have?
Mathematics
1 answer:
Ainat [17]2 years ago
6 0

Lzzy has three more quarters ($0.25) than she has dimes ($0.10), twice as many nickels ($0.05) as she has dimes, and four times as many pennies ($0.01) as she has dimes.

<em>Let us assume number of dimes = x.</em>

<em>"Three more quarters than dimes" would be = (x+3) quarters .</em>

<em>"Twice as many nickels as dimes " would be = (2x) nickels.</em>

<em>"Four times as many pennies as dimes" would be =(4x) pennies.</em>

Total value of all coins = $7.61.

We can setup an equation now.

0.10*x + 0.25(x+3) + 0.05(2x)+0.01(4x)=7.61.

Let us simplify the equation.

0.10x + 0.25x + 0.75 + 0.10x + 0.04x = 7.61

0.49x + 0.75 = 7.61.

Subtratcing 0.75 from both sides, we get

0.49x = 6.86

Dividing both sides by 0.49, we get

x= 14.

Therefore,

<h3>Number of dimes = x = 14.</h3><h3>Number of quarters = (x+3) = 14+3 = 17.</h3><h3>Number of nickels = 2x = 2*14 = 28.</h3><h3>Number of pennies = 4x = 4*14 = 56.</h3>
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There are 24 boys and 16 girls in a hall, each holding coins in their hand.The mean number of coins for the children is 11, The
Karolina [17]

Answer:

14

Step-by-step explanation:

The computation of the mean number of coins for the girls is shown below:

Since there are 24 boys and 16 girls so the total children is 40

So the number of coins for all children is

= 40 × 11

= 440

And, the number of coins for all boys is

= 9 × 24

= 216

Now the mean is

= (440 - 216) ÷ 16 girls

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4 0
2 years ago
The cost of six hens and one duck at the university poultry farm is GH₵40. While four hens and three ducks cost GH₵36. What is t
Anon25 [30]

Answer:

Step-by-step explanation:

Let's call hens h and ducks d. The first algebraic equation says that 6 hens (6h) plus (+) 1 duck (1d) cost (=) 40.

The second algebraic equations says that 4 hens (4h) plus (+) 3 ducks (3d) cost (=) 36.

The system is

6h + 1d = 40

4h + 3d = 36

The best way to go about this is to solve it by substitution since we have a 1d in the first equation. We will solve that equation for d since that makes the most sense algebraically. Doing that,

1d = 40 - 6h.

Now that we know what d equals, we can sub it into the second equation where we see a d. In order,

4h + 3d = 36 becomes

4h + 3(40 - 6h) = 36 and then simplify. By substituting into the second equation we eliminated one of the variables. You can only have 1 unknown in a single equation, and now we do!

4h + 120 - 18h = 36 and

-14h = -84 so

h = 6.

That means that each hen costs $6. Since the cost of a duck is found in the bold print equation above, we will sub in a 6 for h to solve for d:

1d = 40 - 6(6) and

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d = 4.

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3 0
3 years ago
5x+2y = 19<br> 1x + 4y=13
Mama L [17]

Answer:

{x,y} = {25/9,23/9}

Step-by-step explanation:

// Solve equation [2] for the variable  x  

 

 [2]    x = -4y + 13

// Plug this in for variable  x  in equation [1]

  [1]    5•(-4y+13) + 2y = 19

  [1]     - 18y = -46

// Solve equation [1] for the variable  y  

  [1]    18y = 46  

  [1]    y = 23/9  

// By now we know this much :

   x = -4y+13

   y = 23/9

// Use the  y  value to solve for  x

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3 years ago
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makkiz [27]
Hello! 

I was looking for this answer as well, but I took the quiz and got it correct. The answer is 5 units. 

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3 years ago
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