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3 years ago

Find(x)=-x^2-4x+13 find f(3)

Mathematics

1 answer:

hichkok12 [17]3 years ago

5 0

Answer: $f(3)=-8$

Step-by-step explanation:

$f(x)=-x^2-4x+13\\f(3)=-(3)^2-4(3)+13\\f(3)=-(9)-12+13\\f(3)=-9+1\\f(3)=-8$

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Step-by-step explanation:

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Step-by-step explanation:

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Is 1/3, 2/3, 4/3, 8/3, 16/3 arithmetic sequence

11111nata11111 [884]

The given sequence is not arithmetic sequence

Solution:

Given sequence is:

$\frac{1}{3} , \frac{2}{3} , \frac{4}{3} , \frac{8}{3} , \frac{16}{3}$

We have to find if the above sequence is arithmetic sequence or not

An arithmetic sequence is a sequence of numbers such that the difference of any two successive members of the sequence is a constant

Here in the given sequence

$\text{ first term } = a_1 = \frac{1}{3}\\\\\text{ second term } = a_2 = \frac{2}{3}\\\\\text{ third term } = a_3 = \frac{4}{3}\\\\\text{ fourth term } = a_4 = \frac{8}{3}\\\\\text{ fifth term } = a_5 = \frac{16}{3}$

Let us find the difference between terms

$a_2 - a_1 = \frac{2}{3} - \frac{1}{3} = \frac{1}{3}$

$a_3 - a_2 = \frac{4}{3} - \frac{2}{3} = \frac{2}{3}$

$a_4 - a_3 = \frac{8}{3} - \frac{4}{3} = \frac{4}{3}$

$a_5 - a_4 = \frac{16}{3} - \frac{8}{3} = \frac{8}{3}$

Thus the difference between terms is not constant

So the given sequence is not arithmetic sequence

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Answer:

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Step-by-step explanation:

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Maksim231197 [3]

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