3 years ago

Desiree starts a savings account with $125. Every month she deposits $53.50

Mathematics

1 answer:

aev [14]3 years ago

3 0

Answer:

if she deposits for 12 months she would have to deposit 642.

Step-by-step explanation:

You might be interested in

If the cost price of 21 article is equalto the selling price of 18 articles. Find profit precent

d1i1m1o1n [39]

Answer:

The selling price of 21 articles is equal to the cost price of 18 articles. Find the loss percent. Answer: answer is 100/7 %

3 0

3 years ago

-6=-8+<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bp%7D%7B11%7D%20" id="TexFormula1" title=" \frac{p}{11} " alt=" \frac{p}

vekshin1

P=22 rewrite the question as -8+p/11=-6 then move all terms not containing p to the right side p/11=2 multiply both sides of the given equation by 11, the reciprocal, 11*p/11=11*2

8 0

3 years ago

What is the value of x please hurry

harkovskaia [24]

It has to be 36 because it the same stick as the other stick that is telling 36

3 0

3 years ago

Read 2 more answers

Angle a and angle b are verticle angles if m <br> PLEASE HELPLO

klemol [59]

Can we get a picture please

3 0

3 years ago

A statistician uses Chebyshev's Theorem to estimate that at least 15 % of a population lies between the values 9 and 20. Use thi

rjkz [21]

Answer:

\mu = 14.5\\

\sigma = 5.071\\

k = 1.084

Step-by-step explanation:

given that a statistician uses Chebyshev's Theorem to estimate that at least 15 % of a population lies between the values 9 and 20.

i.e. his findings with respect to probability are

$P(9$

Recall Chebyshev's inequality that

$P(|X-\mu |\geq k\sigma )\leq {\frac {1}{k^{2}}}\\P(|X-\mu |\leq k\sigma )\geq 1-{\frac {1}{k^{2}}}\\$

Comparing with the Ii equation which is appropriate here we find that

$\mu =14.5$

Next what we find is

$k\sigma = 5.5\\1-\frac{1}{k^2} =0.15\\\frac{1}{k^2}=0.85\\k=1.084\\1.084 (\sigma) = 5.5\\\sigma = 5.071$

Thus from the given information we find that

$\mu = 14.5\\\sigma = 5.071\\k = 1.084$

5 0

4 years ago