The sum of the 8 terms of the series 1-1-3-5- ... -13 is -48
The given sequence is:
1,-1,-3, . . -13
and there are 8 terms.
The related series of this sequence is:
1-1-3-5- ... -13
Notice that the series is an arithmetic series with:
first term, a(1) = 1
common difference, d = -1 - (1) = -2
last term, a(8) = -13
To find the sum of the series, use the sum formula:
S(n) = n/2 [(a(1) + a(n)]
Substitute n = 8, a(1) = 1, a(n) = a(8) = -13 into the formula:
S(8) = 8/2 [1 + (-13)]
S(9) = 4 . (-12) = -48
Learn more about sum of a series here:
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A is the correct answer I just took the quiz
Since you cannot add numbers which have x to the power of something and normal x, A and B are incorrect. C is also incorrect because I don't even know how you could get that number.
D is correct.
(14x2 + 7x) + 9x2 - you don't even need the brackets, so
14x2 + 7x + 9x2
(14x2 + 9x2) + 7x
23x2 + 7x
Answer:Pretty sure it’s D
Step-by-step explanation: 1.01 is more then .65 but less less than 1.05 as you can tell by the hundreds place.
I hope this helps you
6.9+13
54+13
67
