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cluponka [151]
3 years ago
9

AYONEED HELP WITH THISDONT WANNA FAIL YO

Mathematics
2 answers:
viktelen [127]3 years ago
7 0
B. They are congruent
Brums [2.3K]3 years ago
5 0

Answer:

B

Step-by-step explanation:

angle 5 and angle 7 will add up 180

since angle 5 is congruent to angle 1 then angle 5 equals 120

angle 7 will come out to 60 degrees

180-120=60

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Lea and her father arrived at the scenic overlook 15 minutes before noon and left 12 minutes after noon using am or pm write the
Aneli [31]

Answer:

They arrived at am and left at pm

Step-by-step explanation:

What do you need to find?

We need to find the time when Lea and her father arrived at the scenic overlook and the time when they left.

What do you need to find first?

First we need to find the exact minutes they arrived and left. Then we have to determine whether it was am or pm

Steps:

1. Noting the time they arrived

   They arrived 15 minutes before noon

2. Determining whether it was am or pm

   Noon is 12 pm by convention

   Midnight is 12 am by convention

3. Calculating the minutes for exact time

Each hour has 60 minutes:

60 - 15 = 45

4. Determining the time(am or pm) after subtracting 15 minutes

which means they arrived at 11:45 am (am is used for time before 12 at noon)

5. They left 12 minutes after the noon:

    Noon time is 12 pm

6. Adding 12 minutes to 12pm

    The exact time becomes 12:12pm

4 0
3 years ago
Solve sin4xcos2x-cos4xsin2x=square root of 2 sinx over the interval [0,2pi)
ddd [48]
\bf sin({{ \alpha}} - {{ \beta}})=sin({{ \alpha}})cos({{ \beta}})- cos({{ \alpha}})sin({{ \beta}})
\\\\\\
sin(2\theta)=2sin(\theta)cos(\theta)\\\\
-------------------------------\\\\
sin(4x)cos(2x)-cos(4x)sin(2x)=\sqrt{2}sin(x)
\\\\\\
sin(4x~~-~~2x)=sin(x)\sqrt{2}\implies sin(2x)=sin(x)\sqrt{2}
\\\\\\


\bf 2sin(x)cos(x)=sin(x)\sqrt{2}\implies 2sin(x)cos(x)-sin(x)\sqrt{2}=0
\\\\\\
sin(x)~[2cos(x)-\sqrt{2}]=0\\\\
-------------------------------\\\\
sin(x)=0\implies \measuredangle x=0~~,~~\pi \\\\
-------------------------------\\\\
2cos(x)-\sqrt{2}=0\implies 2cos(x)=\sqrt{2}\implies cos(x)=\cfrac{\sqrt{2}}{2}
\\\\\\
\measuredangle x=\frac{\pi }{4}~~,~~\frac{7\pi }{4}

now, we're not including the III and II quadrants, where the cosine has an angle of the same value, but is negative, because the exercise seems to be excluding the negative values of √(2).
7 0
4 years ago
Help me school is about to start please help
White raven [17]
The formula is 1/2bh(h). multiply the base times the height then multiply that by the other height and divide the sum by two
5 0
3 years ago
3) The area of a square is 20.275 cm². Calculate the side length of the square correct to 4 sf.
timurjin [86]

Answer:

4.502

Step-by-step explanation:

Area of a square is given by

A=L*L = Length squared

20.275=L squared

Applying the square root to both sides of the equation gives L= 4.50222...

L = 4.502 correct to 4 significant figures

3 0
3 years ago
Please help i have been stuck on this for so long :(
sergey [27]

Answer:

Angle 1

Step-by-step explanation:

Angle 1 is the only marked angle that is an obtuse angle (larger than 90 degrees, but less than 180).

Also, the angle marked as 28 degrees and angle one are supplementary, meaning that they add up to equal 180. 180-152=28

7 0
3 years ago
Read 2 more answers
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