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ludmilkaskok [199]
3 years ago
14

Container A has radius ​r​ and height h . It holds a maximum of 44 ounces of water. Container B has radius 2.5r and height 4h .

What is the maximum amount of water that container B can hold?
Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
7 0
Set an equation:

\pi  r^{2} h=44
divide both sides by 3.14
r^{2} h=14

\pi  (2.5r)^{2} 4h=x
divide both sides by 6.25, 4, and 3.14
r^{2} h=x/78.5

Since these two equations are equal, we can set them up that way.

x/78.5=14
multiply both sides by 78.5
x=1099

Answer: The maximum amount of water that container B can hold is 1,099 ounces. 

liq [111]3 years ago
6 0
Pi r^2 h = 44
pi (2.5r)^2 * (4h) = Volume of water = V
V = (2.5)^2  *4 * pir^2h = (2.5)^2 *4 * 44 = 1100
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