Container A has radius r and height h . It holds a maximum of 44 ounces of water. Container B has radius 2.5r and height 4h .
What is the maximum amount of water that container B can hold?
2 answers:
Set an equation:

=44
divide both sides by 3.14

=14

divide both sides by 6.25, 4, and 3.14

=x/78.5
Since these two equations are equal, we can set them up that way.
x/78.5=14
multiply both sides by 78.5
x=1099
Answer: The maximum amount of water that container B can hold is 1,099 ounces.
Pi r^2 h = 44
pi (2.5r)^2 * (4h) = Volume of water = V
V = (2.5)^2 *4 * pir^2h = (2.5)^2 *4 * 44 = 1100
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