Answer:
=
+
+
Step-by-step explanation:
=multiple ways to climb a tower
When n = 1,
tower= 1 cm
= 1
When n = 2,
tower =2 cm
= 2
When n = 3,
tower = 3 cm
it can be build if we use three 1 cm blocks
= 3
When n = 4,
tower= 4 cm
it can be build if we use four 1 cm blocks
= 6
When n > 5
tower height > 4 cm
so we can use 1 cm, 2 cm and 4 cm blocks
so in that case if our last move is 1 cm block then will be
n —1 cm
if our last move is 2 cm block then will be
n —2 cm
if our last move is 4 cm block then will be
n —4 cm
=+ +
415
8*50 + 15
Mark brainliest please
Answer:
m<RPQ = 22°
Step-by-step explanation:
Given:
m<SRQ = 90°
PS = PQ
m<SQR = 46°
Required:
m<RPQ
Solution:
m<SQR + m<SRQ + m<RSQ = 180°
Substitute
46° + 90° + m<RSQ = 180°
m<RSQ = 180° - 136°
m<RSQ = 44°
Find m<PSQ:
m<PSQ = 180° - m<RSQ (Angles on a straight line
m<PSQ = 180° - 44° (Substitution)
m<PSQ = 136°
Find m<RPQ:
∆QSP is an isosceles triangle with two equal base angles. Therefore:
m<RPQ = ½(180° - 136°)
m<RPQ = 22°
Answer:
-3
Step-by-step explanation:
30/(-2)-(-3)(4)
BIDMAS
-15 - (-3)(4)
-15 - -12
-15+12
-3
