(1/2)[logb(b^2)+logb(8x)]
=(1/2)[2+logb(8x)]
=1+(1/2)logb(8x)
hope this helps you
Answer:
Step-by-step explanation:
are we solving this ?
Use the Pythagorean Theorem. If you find the sum of the two legs squared (81+144), you get 225. Take the square root and you get 15. Now add 9+12+15. The perimeter is the sum: 36.
A + 4(a - 5) = 5
a + 4a - 20 = 5
5a = 5 + 20
5a = 25
a = 25/5
a = 5 <====
Step-by-step explanation:
16 - 4(3x - 5)
16 - 12x + 20
12x = 16 + 20
12x = 36
x = 36/12
x = 3
