Answer:
As you have written
Z Y = 3 X Y,
It means X, Y, Z are collinear points i.e they lie in the same line or line segment.
Locating points X, Y,Z on the line
Two possibilities are possible
1. First Z, then X and then Y on the line or line segment
→ Z X + Y X= Z Y
But Z Y = 3 X Y [ Given]
→ Z X + Y X = 3 X Y
→ Z X = 3 X Y - Y X
→ Z X = 2 X Y ⇒ which is not the result.
2. 2nd Possibility
First Z, then Y and then X on the line or line segment
→ Z X = Z Y + Y X
→ Z X= 3 X Y + Y X [Z Y=3 X Y→(given)]
→ Z X= 4 X Y , Which is the result.
Answer:
Step-by-step explanation:
The first differences of the sequence are ...
- 5-2 = 3
- 10-5 = 5
- 17-10 = 7
- 26-17 = 9
- 37-26 = 11
Second differences are ...
- 5 -3 = 2
- 7 -5 = 2
- 9 -7 = 2
- 11 -9 = 2
The second differences are constant, so the sequence can be described by a second-degree polynomial.
We can write and solve three equations for the coefficients of the polynomial. Let's define the polynomial for the sequence as ...
f(n) = an^2 + bn + c
Then the first three terms of the sequence are ...
- f(1) = 2 = a·1^2 + b·1 + c
- f(2) = 5 = a·2^2 +b·2 + c
- f(3) = 10 = a·3^2 +b·3 +c
Subtracting the first equation from the other two gives ...
3a +b = 3
8a +2b = 8
Subtracting the first of these from half the second gives ...
(4a +b) -(3a +b) = (4) -(3)
a = 1 . . . . . simplify
Substituting into the first of the 2-term equations, we get ...
3·1 +b = 3
b = 0
And substituting the values for a and b into the equation for f(1), we have ...
1·1 + 0 + c = 2
c = 1
So, the formula for the sequence is ...
f(n) = n^2 + 1
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The 20th term is f(20):
f(20) = 20^2 +1 = 401
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<em>Comment on the solution</em>
It looks like this matches the solution of the "worked example" on your problem page.
Answer:3/4
Step-by-step explanation:
Multiply 1/6 by 2 to get 2/12 and then add that to 7/12 and get 9/12
If you simplify that you end up with 3/4
Answer:
It will be smaller than one
Step-by-step explanation:
because i said so
Answer: 4 1/6
Step-by-step explanation:
