Suppose f and g are continuous functions such that g(3) = 6 and lim x → 3 [3f(x) + f(x)g(x)] = 54. find f(3).

Solve 11 ≤ w + 3.4 i dont know the answer please help me

shepuryov [24]

Answer:

7.6 ≤w

Step-by-step explanation:

Hey there!

In order to solve this inequality, you need to simplify the inequality like the following:

Subtract 3.4 from both sides

7.6 ≤w

This means that w is greater than or equal to 7.6

6 0

2 years ago

The population of a particular country was 26 million in 1981; in 1990, it was 31 million. the exponential growth function descr

yuradex [85]

Just use syblol it is verygood for varible form

5 0

3 years ago

Jayne says that 0.45 is equal to 4/10. Is she correct? Explain.

yKpoI14uk [10]

No, 4/10 is equal to 0.40 and not 0.45 since 4/10 goes in tens.

4 0

3 years ago

Read 2 more answers

HELP ME PLEASE!

shusha [124]

Answer:

Part A) The probability is closer to 0, because is less than 50%

Part B) The probability is closer to 1, because is greater than 50%

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.

The size of the sample space is the total number of possible outcomes

The event space is the number of outcomes in the event you are interested in.

so

Let

x------> size of the event space

y-----> size of the sample space

so

$P=\frac{x}{y}$

Part A) Is the probability of hitting the black circle inside the target closer to 0 or 1?

In this problem we have

x------> is the area of the black circle

y------> is the total area of the square target

Find the area of black circle

$r=3/2=1.5\ units$

$x=(3.14)(1.5)^{2} =7.065\ units^{2}$

Find the total area of the square target

$y=9^{2}=81\ units^{2}$

Find the probability

$P=\frac{7.065}{81}=0.0872$

Convert to percentage

$0.0872*100=8.72\%$

The probability is closer to 0, because is less than 50%

Part B) Is the probability of hitting the white portion of the target closer to 0 or 1?

In this problem we have

x------> is the area of the white portion of the target

y------> is the total area of the square target

Find the area of the white portion

The area is equal to the area of the square minus the area of the circle

$x=81-7.065=73.935\ units^{2}$

Find the probability

$P=\frac{73.935}{81}=0.9128$

Convert to percentage

$0.9128*100=91.28\%$

The probability is closer to 1, because is greater than 50%

4 0

3 years ago

A group of 100 people is divided into 2 teams with 45 people in team A and 55 people in team B.

Zepler [3.9K]

Team A) 45 people
Team B) 55 people

A)There are two ways to solve this problem, finding the number of combinations possible for Team B, or the number of combinations possible for Team A.
Team A
It's a given that 20 mathematicians are on team A, which leavs the other 25 people for team A to be chosen from a pool of 80 (100- 20 mathletes)
80-C-25 = 80! / (25!/(80-25)!) =363,413,731,121,503,794,368
or 3.63 x 10^20
Solving using Team B
Same concept, but choosing 55 from a pool of 80 (mathletes excluded)
80-C-25 = 80! / (55!(80-55!) = 363,413,731,121,503,794,368
or 3.63 x 10^20

As you can, we get the same answer for both.

B)
If none of the mathematicians are on team A, then we exclude the 20 and choose 45:
80-C-45 = 80! / (45!(80-45)!) = 5,790,061,984,745,3606,481,440
or 5.79 x 10^22

Note that, if you solve from the perspective of Team B (80-C-35), you get the same answer

7 0

3 years ago