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Lady_Fox [76]
3 years ago
7

7*h =14/33 what is h

Mathematics
1 answer:
Setler [38]3 years ago
3 0
7h = 14/33
÷7      ÷7
h = 2/33
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What is the simplified expression of 5(3m+7) - 4?
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Step-by-step explanation:

5(3m+7) - 4 = 15m + 35 - 4 = 15m +31

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Find the equation of the line with slope m=15 that contains the point (−10,−5).
marin [14]

Answer:

Step-by-step explanation:

we know the slope is 15, and contains these points (-10,-5)

y=15x+b

Plug in x and y with those points.

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Solve for x. x3 = 343 A) 6 B) 7 C) 8 D) 9
castortr0y [4]
The answer is:  [B]:  " 7 " .
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Note:  Given:  " x³ = 343 " ;  Solve for "x" ; 
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     ∛(343) = 7 .
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    7³  =  7 × 7 × 7 = 343 .
 7³  =  7 × 7 × 7 =
→  7³  =  7 × 7 × 7 = 49 * 7 = 343 . 
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What is the 1st term when –5z2 + 7z4 + 11z – 8z3 is arranged in descending order?
djverab [1.8K]
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7. Consider the purchase of two cereal boxes.
AveGali [126]

Answer:

a) 0.25

b) 0.25

c) 0.0625

Step-by-step explanation:

The complete question is:

Do you remember when breakfast cereal companies placed prizes in boxes of cereal? Possibly you recall that when a certain prize or toy was particularly special to children, it increased their interest in trying to get that toy. How many boxes of cereal would a customer have to buy to get that toy? Companies used this strategy to sell their cereal.

One of these companies put one of the following toys in its cereal boxes: a block (B), a toy watch (W), a toy ring (R), and a toy airplane (A). A machine that placed the toy in the box was programmed to select a toy by drawing a random number of 1 to 4. If a 1 was selected, the block (or B) was placed in the box; if a 2 was selected, a watch (or W) was placed in the box; if a 3 was selected, a ring (or R) was placed in the box; and if a 4 was selected, an airplane (or A) was placed in the box. When this promotion was launched, young children were especially interested in getting the toy airplane.

What is the probability of getting an airplane in the first cereal box?

Since the machine randomly selects toys, each toy has the same probability of being obtained in a cereal box.

Then, the total outcomes are 4 and the probability of getting an airplane in the first cereal box is 0.25 (25%).

What is the probability of getting an airplane in the second cereal box?

Two independent events do not change the probability of occurrence of one event or another.

The probability of getting an airplane in the second cereal box is 0.25 (25%).

What is the probability of getting airplanes in both cereal boxes?

P(1°∩2°)= P(1°) × P(2°) = \frac{1}{4} \times \frac{1}{4} =\frac{1}{16}

P(1°∩2°)= 0.0625 = 6.25%

4 0
3 years ago
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