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kompoz [17]
3 years ago
11

Solve 2sin^2x=sinx, if 0

Mathematics
1 answer:
Lorico [155]3 years ago
7 0
Explanation:
sin
x
(
2
sin
x
+
1
)
=
0

Use trig table and unit circle -->
a. sin x = 0 => x = 0, and
x
=
π
and
x
=
2
π
b. 2sin x + 1 = 0 =>
sin
x
=
−
1
2
=>
x
=
7
π
6
and
x
=
11
π
6
.
Finally, within interval
[
0
,
2
π
]
,
there are 5 answers:
0
,
π
,
2
π
,
7
π
6
and
11
π
6
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Answer:

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Step-by-step explanation:

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