Answer:
C
Step-by-step explanation:
note y = f(x) = 0
y = 0 is the x- axis
We are looking for values of x on the x- axis where the graph crosses/touches
This occurs at
x = - 2, x = 1, x = 3 → C
To find the number of wrappers he needs, divide 360 by 40. This is your answer. 360/40 = 9
All you need to do to find the slope here is put it into y = mx + b format.
5y + 6x - 2 = 0
the goal is to get the y alone, so...
5y = 2 - 6x
divide both sides by 5
y = 2/5 - (6/5)x
then, just to be clearer for y = mx + b ...... y = (-6/5)x + (2/5)
the slope should be (-6/5)
