Answer:
2 miles
Step-by-step explanation:
1 in=4miles
0.5 in=2miles
so divide by two on each side
Answer:
The original dimensions of the piece of metal are
Length: 36 inches
Width: 21 inches
Step-by-step explanation:
Let
x ----> the original length pf the piece of metal
y ----> the original width pf the piece of metal
we know that
----> equation A
The volume of the box is equal to

we have



substitute in the formula of volume
----> equation B
substitute equation A in equation B

solve for y


Solve the quadratic equation by graphing
using a graphing tool
The solution is y=21
Find the value of x

therefore
The original dimensions of the piece of metal are
Length: 36 inches
Width: 21 inches
Answer:
The smallest positive integer solution to the given system of congruences is 30.
Step-by-step explanation:
The given system of congruences is


where, m and n are positive integers.
It means, if the number divided by 5, then remainder is 0 and if the same number is divided by 11, then the remainder is 8. It can be defined as



Now, we can say that m>n because m and n are positive integers.
For n=1,


19 is not divisible by 5 so m is not an integer for n=1.
For n=2,



The value of m is 6 and the value of n is 2. So the smallest positive integer solution to the given system of congruences is

Therefore the smallest positive integer solution to the given system of congruences is 30.
The answer would be A. He should use the mean because it is in the center of the data. I hope this helped ^^
Answer:
The smallest value of p+q is 11
It happens when p = 6 and q = 5.
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Explanation:
Let's factor 180 in such a way that exactly one factor is a perfect square.
I'll ignore the trivial factor of 1.
Here are the possible factorizations we could go with:
180 = 4*45
180 = 9*20
180 = 36*5
Those factorizations then lead to the following

Then we have
p+q = 2+45 = 47
p+q = 3+20 = 23
p+q = 6+5 = 11
The smallest value of p+q is 11 and it happens when p = 6 and q = 5.
Side note: p+q is smallest when we go with the largest perfect square factor.