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3 years ago

What is the volume of a hemisphere with a radius of 30.8 cm, rounded to the nearest tenth of a cubic centimeter?

Mathematics

1 answer:

den301095 [7]3 years ago

4 0

61194.2707cm³
I suck at rounding so this is the answer not rounded

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Plz help I have to do a test tomorrow on this!

melomori [17]

What do you need help with? Nothing is showing :/

4 0

3 years ago

What is the slope of a line? With the equation d=420-65t

9966 [12]

The slope is the change in y divided by the change in x.

The slope is the ratio of rise to run.

The slope is the rate of change of the function at a certain point.

The slope is the first derivative of a function.

Accordingly, the slope of this line d=420-65t is the coefficient of variable "t" if we consider that d for the dependent variable and t for the independent

Therefore

slope = - 65

I hope you got the idea

7 0

3 years ago

Find the determinant of A. A.29 B.2 C.-2 D.13

strojnjashka [21]

Answer:

Step-by-step explanation:

The determinant of a matrix is a special number that can be calculated from a square matrix.

...

To work out the determinant of a 3×3 matrix:

Multiply a by the determinant of the 2×2 matrix that is not in a's row or column.

Likewise for b, and for c.

Sum them up, but remember the minus in front of the b.

7 0

3 years ago

A company has developed a training procedure to improve scores on the SAT. Following the training, 100 high school students take

Pani-rosa [81]

Answer:

The calculated t-test = 1.717 < 1.6604 at 0.05 level of significance

Null hypothesis is accepted at 0.05 level of significance

A company has developed a training procedure is significantly improve scores

Step-by-step explanation:

Step(i):-

Given sample mean (x⁻ ) = 517

sample standard deviation (s) =90

Mean of the Population (μ) =500

Null Hypothesis :- H₀ : (μ) =500

Alternative Hypothesis : H₁ : μ ≠ 500

Step(ii):-

Test statistic

$t = \frac{x^{-} -mean}{\frac{s}{\sqrt{n} } }$

$t = \frac{517 -500}{\frac{90}{\sqrt{100} } }$

t = 1.717

Level of significance

∝ = 0.05

t₀.₀₅ = 1.6604

The calculated t-test = 1.717 < 1.6604 at 0.05 level of significance

Conclusion:-

Null hypothesis is accepted at 0.05 level of significance

A company has developed a training procedure is significantly improve scores

3 0

3 years ago

Martin was going to the market to buy apples. The price for apples is $3.50 times the number of apples bought plus one-dollar ta

boyakko [2]

A(n) = 3.50n + 1.00

Martin bought 3^3 apples or 27 apples.

Let n = 27

A(27) = 3.50(27) + 1.00

A(27) = $95.50

3 0

3 years ago