Divide 1414 by 55 and you get 25.7 but you can't take .7 collections so the correct answer is 25 collections of 55 books
nshs = sshs+5
wshs = nshh + 6 = sshs + 11
So nshs + wshs + sshs = 3*sshs + 16
So sshs = 10, nshs = 15 and wshs = 21
Answer 15.
Answer:
6
Step-by-step explanation:
The mode is the number which appears most often in a set of numbers in this case that would be 6 because it appears twice
Answer:
y = 3 and y = x + 3
Step-by-step explanation:
The equation y = 3 whose graph is a line parallel to x-axis can be a part of the system.
Consider the equation y = x + 3.
Substitute (0, 3).
3 = 0 + 3
So, (0, 3) lies on y = x + 3 and this can also be a part of the system.
The valid exclusion of the algebraic fraction is (c) a =0, b =0, a =2b
<h3>How to determine the valid exclusion?</h3>
The expression is given as:
8ab^2x/4a^2b - 8ab^2
Set the denominator to 0
4a^2b - 8ab^2 = 0
Divide through by 4ab
a - 2b = 0
Add 2b to both sides
a = 2b
Hence, the valid exclusion of the algebraic fraction is (c) a =0, b =0, a =2b
Read more about algebraic fraction at:
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