What is the solution to 3^x = 5

Anthony who is 5 feet tall stands 20 feet from a lamppost and casts a shadow that is 10 feet long. If he moves 5 feet closer to

Sophie [7]

15 feet tall
would be his shadow

3 0

2 years ago

Suppose you just received a shipment of nine televisions. Three of the televisions are defective. If two televisions are randoml

Temka [501]

<h2>Answer:</h2>

a)

The probability that both televisions work is: 0.42

b)

The probability at least one of the two televisions does not work is:

0.5833

<h2>Step-by-step explanation:</h2>

There are a total of 9 televisions.

It is given that:

Three of the televisions are defective.

This means that the number of televisions which are non-defective are:

9-3=6

a)

The probability that both televisions work is calculated by:

$=\dfrac{6_C_2}{9_C_2}$

( Since 6 televisions are in working conditions and out of these 6 2 are to be selected.

and the total outcome is the selection of 2 televisions from a total of 9 televisions)

Hence, we get:

$=\dfrac{\dfrac{6!}{2!\times (6-2)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{\dfrac{6!}{2!\times 4!}}{\dfrac{9!}{2!\times 7!}}\\\\\\=\dfrac{5}{12}\\\\\\=0.42$

b)

The probability at least one of the two televisions does not work:

Is equal to the probability that one does not work+probability both do not work.

Probability one does not work is calculated by:

$=\dfrac{3_C_1\times 6_C_1}{9_C_2}\\\\\\=\dfrac{\dfrac{3!}{1!\times (3-1)!}\times \dfrac{6!}{1!\times (6-1)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{3\times 6}{36}\\\\\\=\dfrac{1}{2}\\\\\\=0.5$

and the probability both do not work is:

$=\dfrac{3_C_2}{9_C_2}\\\\\\=\dfrac{1}{12}\\\\\\=0.0833$

Hence, Probability that atleast does not work is:

0.5+0.0833=0.5833

4 0

3 years ago

Emma bought three cans of tennis balls for $4 each. Sales tax for all three cans was $0.95. Wh

LiRa [457]

Answer:

4(3)+0.95=X

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Hey Guys, Thank you for all your help and support. I was wondering if you could help me one last time, I'm really confused. Than

SCORPION-xisa [38]

(-2,-3) is the answer to the first part

5 0

2 years ago

How to multiply decimals when not using models

sukhopar [10]

Answer:

You multiply it like normal numbers. But when you do, count how many numbers are behind the decimal, say there are 2 numbers behind the decimal, once you finished multiplying the numbers you would add up all the products you got and then put the first 4 numbers you wrote behind the decimal to get the final product.

Step-by-step explanation:

Say you were multiplying 14.63 and 7.74

14.63

<u> x 7.74 </u><em>Always starting from the right side of the equation</em>

.5852 <em>go to the left </em> <em>four digits and put a decimal then </em>

<em> ↑←←←← just carry the decimal down and you'll end up with </em>

10.2410 <em>the final product</em>

113.2362

8 0

2 years ago