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ELEN [110]
3 years ago
15

Of 1414 possible​ books, you plan to take 55 with you on vacation. how many different collections of 55 books can you​ take?

Mathematics
1 answer:
Svetach [21]3 years ago
4 0
Divide 1414 by 55 and you get 25.7 but you can't take .7 collections so the correct answer is 25 collections of 55 books
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Solve -9-8(1+4h)=-17
Mariulka [41]
-9-8(1+4h) = -17. We need to solve for h.
First, use the distributive property for 8(1+4h):
8(1+4h) = 8*1 + 8*4h = 8 + 32h

So -9-8(1+4h) = -17
-9 - (8+32h) = -17
-9 - 8 - 32h = -17
-17 - 32h = - 17
Add 17 on both sides to have the variables on a side and the numbers on the other:
-17 - 32h + 17 = -17 + 17
-32h = 0
divide both sides by -32 to get the variable h alone and its value on the other side:
(-32h)/-32 = 0/-32
h = 0.

So -9-8(1+4h) = -17 for h = 0.

You can recheck your answer (very important):
-9 - 8(1+4h) = -9 -8(1+4*0) = -9 - 8(1+0) = -9-8*1 = -9-8 = -17
The answer has been approved.

Hope this Helps! :)
5 0
3 years ago
Read 2 more answers
The mean age of Mr Jasmi,Miss Haslinda and their three children is 38 years. The mean age of their three children is 18 years. C
DedPeter [7]
Answer: 68

Explanation:

Let x be the age of Mr Jasmi
y be the age of Miss Haslinda
a + b + c be the age of the 3 children

We can write:
(x + y + a + b + c)/5 = 38

But:
(a + b + c)/3 = 18
a + b + c = 18(3)
a + b + c = 54

Substitute this value to our first equation

(x + y + 54)/5 = 38
x + y + 54 = 38(5)
x + y + 54 = 190
x + y = 190 - 54
x + y = 136

Thus:
Mean age of (mr jasmi and miss Linda) = (x+y)/2

But x + y = 136

=> mean age = 136/2 = 68
4 0
2 years ago
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krek1111 [17]
16*8=128 and 128*12= is 1,536
3 0
3 years ago
Order the values from<br> least to greatest:<br> | -4|,|3|, 0,-1
mrs_skeptik [129]

Answer: -4, -1, 0, 3

8 0
3 years ago
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Pam kept track of the puppies available for adoption at the shelter. After 4 hours, there were 7 puppies available for adoption.
Varvara68 [4.7K]
A. 3 hours is the answer
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3 years ago
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