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Aleksandr-060686 [28]
3 years ago
12

The number of clients arriving at a bank machine is Poisson distributed with an average of 2 per minute. What is the probability

that no more than 2 customers will arrive in a minute
Mathematics
1 answer:
IrinaVladis [17]3 years ago
6 0

Answer:

The probability that no more than '2' customers will arrive in minute = 1.5412

Step-by-step explanation:

Explanation:-

Mean of the Poisson distribution 'λ' = 2 per minute

P(X=x) = e⁻ˣ λˣ/x!

The probability that no more than '2' customers will arrive in minute

P(x≤ 2) = P(x=0) +P(x=1)+P(x=2)

           = e⁻² (2)°/0! + e⁻²(2)¹/1!+e⁻² (2)²/2!

          = 1 + 0.2706 + 0.2706

          = 1.5412

The probability that no more than '2' customers will arrive in minute = 1.5412

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(x+a)(x+b)

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-b^2+4b=-32
b^2-4b-32=0
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If b=8, a=-4
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Please help with these math questions part 2
NikAS [45]
5).
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6 0
3 years ago
If Charles lost 20 pounds, he would weigh seven times as much as his dog. Together they weigh 200 pounds. How much does each wei
barxatty [35]

Answer: Weight of Charles = 177.5 pounds

Weight of dos = 22.5 pounds.

Step-by-step explanation:

Let x = Weight of Charles

y = Weight of dog.

As per given , we have the following system of linear equation :

x+y=200--------(i)\\\\x-20=7y-----------(ii)

We can write (ii) as :

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Subtract equation (iii) from (i) , we get

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Put this value in (1) , we get

x+22.5=200\Rightarrow\ x=200-22.5=177.5

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6 0
3 years ago
5, 3, 2, 6, 7, 9, 1, 15, 4, 2, 3, 3, 9, 5, 1, ?
Shkiper50 [21]

Answer:

I have no idea thank you for the points

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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