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4 years ago

I need help with this question please

Mathematics

1 answer:

Brilliant_brown [7]4 years ago

4 0

A= (0,0)
B=(1,-3)
C=(1,-1)

wtd easy as hell

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What is the product as a sum for (x + 7)(2x – 5)

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Answer:

Step-by-step explanation:

u add both of the x's and add 7 and 2 then u times 7 and 5

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3 years ago

Which best describes a graph of a puppy's weight during its first year of life?

Alenkasestr [34]

The answer will be B! I hope this helps!

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4 years ago

A worker at a landscape design center uses a machine to fill bags with potting soil. Assume that the quantity put in each bag fo

defon

Answer:

a) The expected value is given by:

$E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11$

The variance is given by:

$Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333$

And the standard deviation is just the square root of the variance and we got:

$Sd(x) = \sqrt{0.3333}= 0.5774$

b) $P(X$

And we can use the cumulative distribution function given by:

$F(x) = \frac{x-a}{b-a}, a \leq x \leq b$

And using this function we got:

$P(X$

c) $P(X>10.5)$

And using the complement rule and the cumulative distribution function we got:

$P(X>10.5)= 1-P(X$

Step-by-step explanation:

For this case we define the random variable X=quantity put in each bag , and we know that the distribution for X is given by:

$X \sim Unif (a= 10, b =12)$

Part a

The expected value is given by:

$E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11$

The variance is given by:

$Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333$

And the standard deviation is just the square root of the variance and we got:

$Sd(x) = \sqrt{0.3333}= 0.5774$

Part b

For this case we want this probability:

$P(X$

And we can use the cumulative distribution function given by:

$F(x) = \frac{x-a}{b-a}, a \leq x \leq b$

And using this function we got:

$P(X$

Part c

For this case we want this probability:

$P(X>10.5)$

And using the complement rule and the cumulative distribution function we got:

$P(X>10.5)= 1-P(X$

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4 years ago

7. Here is a polygon:

Afina-wow [57]

Answer:

Step-by-step explanation:

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3 years ago

two comets orbit the Sun. One comet travels 30,000 miles per hour and the other comet travels 28,500 miles per hour. What is the

GenaCL600 [577]

The difference of the distances traveled by the comets for any given number of minutes is 25t.

Since the first comet travels at a speed of 30,000 miles per hour, the distance it travels in t minutes is d = 30000 mph × 1 h/60 min × t = 500t miles.

Also, the second comet travels at a speed of 28,500 miles per hour, the distance it travels in t minutes is d' = 28,500 mph × 1 h/60 min × t = 475t miles.

So, the difference in the distances traveled by the comets D = d - d'

= 500t - 475t

= 25t

So, the difference of the distances traveled by the comets for any given number of minutes is 25t.

Learn more about distance traveled by comets here:

brainly.com/question/11458136

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3 years ago