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denpristay [2]
3 years ago
11

Which of the following would not be a good fuse design? low-melt wire encased in glass low-melt wire encased in ceramic low-melt

wire encased in iron low-melt wire encased in a tube of air
Physics
2 answers:
bazaltina [42]3 years ago
8 0
The wire encased in iron.  This is because iron conducts current so the fuse would still work well above the rated current!
QveST [7]3 years ago
5 0

Answer:

low melt wire encased in glass

Explanation:

Fuse wire is a safety device for an electrical appliance. It works on heating effcet of current. It has low melting point and high resistance.

A fuse wire is a low melting point wire encased in glass.

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Which of the following is an ecosystem
iogann1982 [59]

A it is Green plants.

or they all

7 0
3 years ago
To construct an oscillating LC system, you can choose from a 11 mH inductor, a 6.0 μF capacitor, and a 4.2 μF capacitor. What ar
Free_Kalibri [48]

Answer:

a. 475.14 Hz

b. 1959 Hz

c. 2341.53 Hz , 3053.34 Hz

Explanation:

f = \frac{1}{2\pi*\sqrt{C*L}}

a. smallest use the capacitive 4.2 uF + 6.0 uF = 10.2uF  replacing:

f = \frac{1}{2\pi*\sqrt{C*L}}f=\frac{1}{2\pi*\sqrt{10.2uF*11mH}}

f = 475.14 Hz

b. second smallest use the capacitive 6 uF so:

f = \frac{1}{2\pi*\sqrt{C*L}}=f = \frac{1}{2\pi*\sqrt{6uF*11mH}}

f = 1959Hz

c. second largest and largest oscillation first combination so:

Use 4.2 uF

f = \frac{1}{2\pi*\sqrt{C*L}}=f = \frac{1}{2\pi*\sqrt{4.2uF*11mH}}

f = 2341.53 Hz

And finally largest oscillation cap in serie so:

C=\frac{c_1*c_2}{c_1+c_2}=\frac{4.2uF*6.0uf}{4.2uf+6.0uF}

C=2.47 uF

f = \frac{1}{2\pi*\sqrt{C*L}}=f = \frac{1}{2\pi*\sqrt{2.47uF*11mH}}

f =  3053.34 Hz

5 0
3 years ago
An object with the mass of 2.0 kg accelerates 2.0 m/s2 when an inknown force is applied to it what is the amount of the force
Ivahew [28]

As per Newton's II law we know that

F = ma

here F = force applied

m = mass of object = 2 kg

a = acceleration = 2 m/s^2

now as per above formula we will have

F = 2 \times 2

F = 4 N

so here applied force on the ball will be 4 N

3 0
3 years ago
Directions: Select the choice that best fits each statement. The following question(s) refer to the following concepts related t
borishaifa [10]

Answer:

(E) Second law of thermodynamics

Explanation:

The second law of thermodynamics can be understood according to Clausius' words: In an isolated system, no process can occur if a decrease in the total entropy of the system is associated with it. These processes are associated with energy transformations, in which a variable is introduced, called entropy that indicates the notion of disorder. Therefore, in any isolated process, the disorder can only grow.

4 0
4 years ago
Read 2 more answers
Assume that you have 0.480 mol of N2 in a volume of 0.700 L at 300 K .
Svetach [21]

Answer:

1) 16.88 atm

2) 34.47 atm

Explanation:

Data:

Volume=0.700L

Temperature = 300K

Number of moles=0.480 mol

Ideal gas constant=0.082057 L*atm/K·mol

1) The ideal gas law is:

PV=nRT (1)

with P the pressure, T the temperature, n the number of moles, V the volume and R the ideal gas constant , so solvig (1) for P:

P=\frac{nRT}{V}

P=\frac{(0.480)(0.082057)(300)}{0.700}=16.88 atm

2) The vander Walls equation is:

(P+\frac{a}{V^{2}})(V-b)=RT

solving for P

P=\frac{RT}{V-b}-\frac{a}{V^2}=\frac{(0.082057)(300)}{0.700-0.0387}-\frac{1.35}{0.700^2}=34.47 atm

4 0
3 years ago
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