1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mr Goodwill [35]
3 years ago
12

The electric field strength E 0 E 0 is measured at a perpendicular distance R R from an infinitely large, thin sheet that contai

ns a uniform positive charge density σ . σ. In terms of the stated properties and the permittivity of free space ε 0 , ε0, write an expression for the electric field strength E E at a perpendicular distance 2 R 2R from the sheet.
Physics
1 answer:
IRISSAK [1]3 years ago
5 0

Answer:

same value in R and 2R       E = E₀ = σ / 2ε₀

Explanation:

For this exercise we use Gauss's law

            Ф = E. dA = q_{int} /ε₀

We define a Gaussian surface with a cylinder with the base being parallel to the load sheet, so the electic field line and the normal line to the base are parallel and the scalar product is reduced to the algebraic product, in the parts the angle is 90º and the dot product is zero

As the sheet has two faces

           2E A = q_{int} /ε₀

The charge inside the cylinder is

           σ = q_{int} / A

           q_{int} = σ A

               

We substitute

           E = σ / 2ε₀

We see that this expression is independent of the distance, so it has the same value in R and 2R

             E = E₀ = σ / 2ε₀

You might be interested in
One ball of mass 0.600kg travelling 9.00m/s to the right collides head on elastically with a second ball of mass 0.300kg travell
Alina [70]

Let m₁ and v₁ denote the mass and initial velocity of the first ball, and m₂ and v₂ the same quantities for the second ball. Momentum is conserved throughout the collision, so

m₁ v₁ + m₂ v₂ = m₁ v₁' + m₂ v₂'

where v₁' and v₂' are the balls' respective velocities after the collision.

Kinetic energy is also conserved, so

1/2 m₁ v₁² + 1/2 m₂ v₂² = 1/2 m₁ (v₁')² + 1/2 m₂ (v₂')²

or

m₁ v₁² + m₂ v₂² = m₁ (v₁')² + m₂ (v₂')²

From the momentum equation, we have

(0.600 kg) (9.00 m/s) + (0.300 kg) (-8.00 m/s) = (0.600 kg) v₁' + (0.300 kg) v₂'

which simplifies to

10.0 m/s = 2 v₁' + v₂'

so that

v₂' = 10.0 m/s - 2 v₁'

From the energy equation, we have

(0.600 kg) (9.00 m/s)² + (0.300 kg) (-8.00 m/s)² = (0.600 kg) (v₁')² + (0.300 kg) (v₂')²

which simplifies to

67.8 J = (0.600 kg) (v₁')² + (0.300 kg) (v₂')²

or

226 m²/s² = 2 (v₁')² + (v₂')²

Substituting v₂' yields

226 m²/s² = 2 (v₁')² + (10.0 m/s - 2 v₁')²

which simplifies to

3 (v₁')² - (20.0 m/s) v₁' - 63.0 m²/s² = 0

Solving for v₁' using the quadratic formula gives two solutions,

v₁' ≈ -2.33 m/s   or   v₁' = 9.00 m/s

but the second solution corresponds to the initial conditions, so we omit that one.

Then the second ball has velocity

v₂' = 10.0 m/s - 2 (-2.33 m/s)

v₂' ≈ 14.7 m/s

6 0
2 years ago
Energy conservation is the process by which one kind of energy changes into a another and when energy is converted this way it's
Sedbober [7]

True. The question describes the idea of energy conservation faithfully. Energy can change forms but remains the same within an isolated system over time. Within such a system, energy cannot be created or destroyed.

7 0
4 years ago
Why does your body feels like it is being pushed back when the car starts back up again
Llana [10]
The acceleration due to gravity is not due to the Earth's motion through space. It is due to the gravitational force pulling you towards the center of mass of the Earth. The ground pushes back<span>, and what you </span>feel<span> is </span>your<span> weight. This is the same as what you </span>feel<span> in an accelerating </span>car<span>.</span>
5 0
4 years ago
The most common liquid on planet earth is
son4ous [18]
The most common liquid on planet earth is water
3 0
4 years ago
A boy rows a rowboat across a river. The boat moves at 4.3 m/s at a direction of 25°
NikAS [45]

East component: 3.9 m/s

South component: 1.8 m/s

Explanation:

We have to resolve the velocity vector along the east and south axis.

Taking east as positive x-direction and south as positive y-direction, the components of the velocity are given by:

v_x = v cos \theta\\v_y = v sin \theta

where

v = 4.3 m/s is the magnitude of the velocity

\theta=25^{\circ} is the angle between the direction of the velocity and of the x-axis

Substituting into the equations, we find:

East component:

v_x = (4.3)(cos 25^{\circ})=3.9 m/s

South component:

v_y = (4.3)(sin 25^{\circ})=1.8 m/s

Learn more about vector components:

brainly.com/question/2678571

#LearnwithBrainly

5 0
4 years ago
Other questions:
  • The weight of an object is the product of its mass m, and acceleration of gravity , g . If an objects mass is m=10 . Kg what is
    12·1 answer
  • What would the answer be ?
    11·1 answer
  • A sound wave travels across a 2,100-meter wide valley in 7.0 seconds.
    8·1 answer
  • Classify the items based on whether they are or are not matter.
    5·1 answer
  • The electrons of an atom are located in regions around the nucleus called?
    14·1 answer
  • Which is an example of species diversity?
    13·1 answer
  • What is the velocity of a dog who travels south 50 meters in 9 seconds
    7·1 answer
  • What is the law of conservation of energy?
    6·1 answer
  • ⦁ A body has weight 10 N. How much force is required to move it vertically upward with an acceleration of 3 ms-2?
    6·1 answer
  • And don't delete this
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!