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Lelu [443]
3 years ago
6

What kind of relationship does a human have with the bacteria that lives in her/his digestive tract?

Physics
1 answer:
Misha Larkins [42]3 years ago
4 0
The one that both benefits each other is the one I think it's mutalistic
You might be interested in
4. The bar has cross-sectional area A and modulus of elasticity E. If an axial force F directed toward the right is applied at C
aniked [119]

Answer:

a)  ΔL/L = F / (E A),  b)   L_{f} = L (1 + L F /(EA) )

Explanation:

Let's write the formula for Young's module

     E = P / (ΔL / L)

Let's rewrite the formula, to have the pressure alone

    P = E ΔL / L

The pressure is defined as

    P = F / A

Let's replace

   F / A = E ΔL / L

   F = E A ΔL / L

   ΔL / L = F / (E A)

b) To calculate the elongation we must have the variation of the length, so the length of the bar must be a fact. Let's clear

    ΔL = L [F / EA]

    L_{f} -L = L (F / EA)

    L_{f} = L + L (F / EA)

    L_{f} = L (1 + L (F / EA))

4 0
3 years ago
WILL GIVE BRAINLIST: Does an objects weight affect how fast it falls?
maw [93]

Answer:

it's depent on height and gravity

5 0
3 years ago
A rail car moving at 10m/s collides with and connect to another stationary car. What is their final velocity?
ki77a [65]

Answer:

read this it might help some

When a moving object collides with a stationary object of identical mass, the stationary object encounters the greater collision force. When a moving object collides with a stationary object of identical mass, the stationary object encounters the greater momentum change.

Explanation:

6 0
3 years ago
Coherent light that contains two wavelengths, 660 nm and 470 nm , passes through two narrow slits with a separation of 0.280 mm
bekas [8.4K]

Answer:

λ1 = 0.0129m = 1.29cm

λ2 = 0.00923m = 0.92 cm

Explanation:

To find the distance between the first order bright fringe and the central peak, can be calculated by using the following formula:

y_m=\frac{m\lambda D}{d}    (1)

m: order of the bright fringe = 1

λ: wavelength of the light = 660 nm, 470 nm

D: distance from the screen = 5.50 m

d: distance between slits = 0.280mm = 0.280 *10^⁻3 m

ym: height of the m-th fringe

You replace the values of the variables in the equation (1) for each wavelength:

For λ = 660 nm = 660*10^-9 m

y_1=\frac{(1)(660*10^{-9}m)(5.50m)}{0.280*10^{-3}m}=0.0129m=1.29cm

For λ = 470 nm = 470*10^-9 m

y_1=\frac{(1)(470*10^{-9}m)(5.50m)}{0.280*10^{-3}m}=0.00923m=0.92cm

7 0
3 years ago
Where is the epicenter of the hypothetical earthquake as shown in the illustration below?
Genrish500 [490]

Answer:

Point D

Explanation:

The epicenter of a hypothetical earthquake is located at the point where the earthquake begins.

(See the attached image).

Hope it helps!

5 0
3 years ago
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