A box is given a push so that it slides across the floor. How far will it go, given that the coefficient of kinetic friction is
1 answer:
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Explanation:
(a) Net force acting on the block is as follows.
or, ma = -mg Sin (\theta)[/tex]
a =
=
= -3.35
According to the kinematic equation of motion,
Distance traveled by the block before stopping is as follows.
s =
=
= 21.5 m
According to the kinematic equation of motion,
v =
0 =
= 7.16 sec
Therefore, before coming to rest the surface of the plane will slide the box till 7.16 sec.
(b) When the block is moving down the inline then net force acting on the block is as follows.
ma =
a =
=
= 3.35
Kinematics equation of the motion is as follows.
s =
21.5 m =
=
= 3.58 sec
Hence, total time taken by the block to return to its starting position is as follows.
t =
= 7.16 sec + 3.58 sec
= 10.7 sec
Thus, we can conclude that 10.7 sec time it take to return to its starting position.