What type of force was applied to these rocks to form folds?

1 answer:

3 0

<span>Folds are caused by compression forces pushing rock together like the ends of a big runner rug or something similar. You press on the ends, and things start to fold up and bunch up in the middle. So horizontal force or compressional force is said to be applied on rocks</span>

You might be interested in

If the accepted value of a wave is 121 m/s, who has the most accurate method of measuring the speed of a wave?

qaws [65]

The answer would be erin out of all of them thank me later :)

5 0

3 years ago

Different kinds of electromagnetic waves are identified by<br> their -?-

const2013 [10]

Answer:

frequency or wavelength

Explanation:

this is why the electromagnetic spectrum has a decreasing wavelength and increasing frequency

4 0

2 years ago

The World-War II battleship U.S.S Massachusetts used 16-inch guns whose barrel lengths were 15 m long. The shells each of mass 1

Vaselesa [24]

Answer:

The explosive force experienced by the shell inside the barrel is 23437500 newtons.

Explanation:

Let suppose that shells are not experiencing any effect from non-conservative forces (i.e. friction, air viscosity) and changes in gravitational potential energy are negligible. The explosive force experienced by the shell inside the barrel can be estimated by Work-Energy Theorem, represented by the following formula:

$F\cdot \Delta s = \frac{1}{2}\cdot m \cdot (v_{f}^{2}-v_{o}^{2})$ (1)

Where:

$F$ - Explosive force, measured in newtons.

$\Delta s$ - Barrel length, measured in meters.

$m$ - Mass of the shell, measured in kilograms.

$v_{o}$ , $v_{f}$ - Initial and final speeds of the shell, measured in meters per second.

If we know that $m = 1250\,kg$ , $v_{o} = 0\,\frac{m}{s}$ , $v_{f} = 750\,\frac{m}{s}$ and $\Delta s = 15\,m$ , then the explosive force experienced by the shell inside the barrel is: