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3 years ago

2x-5<5x-3x Please Help Me!!!

Mathematics

1 answer:

jeyben [28]3 years ago

5 0

Step-by-step explanation:

Check the above photos

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Solve irrational equation pls

rusak2 [61]

$\hbox{Domain:}\\
x^2+x-2\geq0 \wedge x^2-4x+3\geq0 \wedge x^2-1\geq0\\
x^2-x+2x-2\geq0 \wedge x^2-x-3x+3\geq0 \wedge x^2\geq1\\
x(x-1)+2(x-1)\geq 0 \wedge x(x-1)-3(x-1)\geq0 \wedge (x\geq 1 \vee x\leq-1)\\
(x+2)(x-1)\geq0 \wedge (x-3)(x-1)\geq0\wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\\
x\in(-\infty,-2\rangle\cup\langle1,\infty) \wedge x\in(-\infty,1\rangle \cup\langle3,\infty) \wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\\
x\in(-\infty,-2\rangle\cup\langle3,\infty)$

$
\sqrt{x^2+x-2}+\sqrt{x^2-4x+3}=\sqrt{x^2-1}\\
x^2-1=x^2+x-2+2\sqrt{(x^2+x-2)(x^2-4x+3)}+x^2-4x+3\\
2\sqrt{(x^2+x-2)(x^2-4x+3)}=-x^2+3x-2\\
\sqrt{(x^2+x-2)(x^2-4x+3)}=\dfrac{-x^2+3x-2}{2}\\
(x^2+x-2)(x^2-4x+3)=\left(\dfrac{-x^2+3x-2}{2}\right)^2\\
(x+2)(x-1)(x-3)(x-1)=\left(\dfrac{-x^2+x+2x-2}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\left(\dfrac{-x(x-1)+2(x-1)}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\left(\dfrac{-(x-2)(x-1)}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\dfrac{(x-2)^2(x-1)^2}{4}\\
4(x+2)(x-3)(x-1)^2=(x-2)^2(x-1)^2\\$
$
4(x+2)(x-3)(x-1)^2-(x-2)^2(x-1)^2=0\\
(x-1)^2(4(x+2)(x-3)-(x-2)^2)=0\\
(x-1)^2(4(x^2-3x+2x-6)-(x^2-4x+4))=0\\
(x-1)^2(4x^2-4x-24-x^2+4x-4)=0\\
(x-1)^2(3x^2-28)=0\\
x-1=0 \vee 3x^2-28=0\\
x=1 \vee 3x^2=28\\
x=1 \vee x^2=\dfrac{28}{3}\\
x=1 \vee x=\sqrt{\dfrac{28}{3}} \vee x=-\sqrt{\dfrac{28}{3}}\\$

There's one more condition I forgot about
$-(x-2)(x-1)\geq0\\
x\in\langle1,2\rangle\\$

Finally
$x\in(-\infty,-2\rangle\cup\langle3,\infty) \wedge x\in\langle1,2\rangle \wedge x=\{1,\sqrt{\dfrac{28}{3}}, -\sqrt{\dfrac{28}{3}}\}\\
\boxed{\boxed{x=1}}$

3 0

2 years ago

50<br> Σ (4n - 1) = [? ]<br> 1

Kay [80]

Answer:

5050

Step-by-step explanation:

3 0

3 years ago

BIG POINTS!!! (p-.20 p=new price.) "Natasha bought a racket that was marked down 20%" (my equation was in first parenthesis) If

MariettaO [177]

120-(120*20%) = 120-24 = 96
Natasha paid $96.
0.8p represents how much the price was when Natasha paid.

3 0

3 years ago

20 POINTS!!!! <br> HELPPPPP THIS IS DUE TONIGHT!!!!

alexandr1967 [171]

Step-by-step explanation:

Our coordinates are (6, 0) and (0, -3).

We can use the formula (y₂-y₁)/(x₂-x₁) to find the slope-intercept form (y=mx+b)

Now, we plug the coordinates into the formula and solve.

(0-(-3))/(6-0)

=3/6

= $\frac{1}{2}$

So, the slope is $\frac{1}{2}$ .

Now, we have to find the y-intercept, which is the point where the line on the graph intersects with the y-axis.

We can find the y-intercept (which is represented by b) by plugging the information we already know into the formula.

We can use either pair of coordinates for the formula, so I'll use (6, 0).

y=mx+b

0= $\frac{1}{2}$ (6)+b

Now, we can solve.

0=3+b

Subtract 3 from both sides.

-3=b

The y-intercept is -3.

Answer:

y= $\frac{1}{2}$ x-3

7 0

2 years ago

What is the graph description for y=-10x

Serga [27]

Y = - 10x has a negative slope, m = -10, and a y-intercept of (0, 0).

The graph includes the following points:

{(-2, 20), (-1, 10), (0, 0), (1, -10), (2, -20)}.

Attached is a screenshot of the graph, where it includes the y-intercept crossing along the point of origin, (0, 0).

Please mark my answers as the Brainliest, if you find this helpful :)

8 0

2 years ago