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Wewaii [24]
3 years ago
10

Rebecca needs 10 1/2 yards of fabric to make a quilt. She has one piece of fabric that is 2 1/2 yards and another piece of fabri

c that is 4 1/4 yards. How many more yards of fabric does Rebecca still need to make the quilt?
Mathematics
1 answer:
nikdorinn [45]3 years ago
7 0

Answer: 3 3/4 yards. I think.

Step-by-step explanation: 10 1/2=10 2/4 2 1/2=2 2/4

10 2/4 - 2 2/4= 8. 8= 7 4/4. 7 4/4 - 4 1/4= 3 3/4.

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<h3>Given</h3>

The current balance is $420.

The current balance is 7/6 of the original balance, b

<h3>Find</h3>

equation to use to find b

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Equate the two descriptions of the current balance.

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3 0
3 years ago
1: Ken earned $176 from his part-time job this summer. He spent 25% of his money on games. ​He is going to donate 14 of the rema
tatiyna

The charity will receive $ 11

<h3><u>Solution:</u></h3>

Ken earned $176 from his part-time job this summer

Amount earned = $ 176

He spent 25% of his money on games

Therefore,

Money spent on games = 176 - 25 % of 176

\text{Money spent on games } = 176 - \frac{25}{100} \times 176\\\\\text{Money spent on games } = 176 - 0.25 \times 176\\\\\text{Money spent on games } = 176 - 44\\\\\text{Money spent on games } = 132

He is going to donate 1/4 of the remaining money to charity

Reamining amount = 176 - 132 = 44

Therefore,

Money\ given\ to\ charity = \frac{1}{4} \times 44 = 11

Thus he gave $ 11 to charity

8 0
3 years ago
What’s the domain and range of:<br> log(√(2x-1) + 3 )<br> Please explain how you got it too!!
Radda [10]

Two main facts are needed here:

1. The logarithm \log x, regardless of the base of the logarithm, exists for x>0.

2. The square root \sqrt x exists for x\ge0.

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By (2) we know that \sqrt{2x-1} exists if 2x-1\ge0, or x\ge\dfrac12.

By (1), we know that \log(\sqrt{2x-1}+3) exists if \sqrt{2x-1}+3>0, or \sqrt{2x-1}>-3. But as long as the square root exists, it will always be positive, so this condition will always be met.

Ultimately, then, we only require x\ge\dfrac12, so the function has domain \left[\dfrac12,\infty).

To determine the range, we need to know that, in their respective domains, \sqrt x and \log x increase monotonically without bound. We also know that x=\dfrac12 at minimum, at which point the square root term vanishes, so the least value the function takes on is \log3. Then its range would be [\log3,\infty).

3 0
3 years ago
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Answer:

She can make 12 bows ......................................

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