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elena55 [62]
3 years ago
15

Help quick!PLS AND TY!

Mathematics
1 answer:
frosja888 [35]3 years ago
4 0

Answer

8p∠-8

Step-by-step explanation:

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2 + (3 – 2 x 2) *1<br> What’s the answer on this <br> Problem
Pavlova-9 [17]
The answer is 4 or 5
5 0
3 years ago
Name:
Effectus [21]

Answer:

8421  

Step-by-step explanation:

8050 < abcd < 8500

We must have a = 8, so the number is 8bcd.

The value of a is 20 times the value of b, or a= 2b.

a = 8, so b = 4.

The value of b is 20 times the value of c, or b = 2c.

b = 4, so c = 2.

The value of c is 20 times the value of d, or c = 2d.

c = 2, so d = 1.

The secret number is 8421.

8 0
3 years ago
What is the correct answer of 2+2*3+2*2+4=?
Diano4ka-milaya [45]
2+2*3+2*2+4
=2+6+4+4
=16
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3 years ago
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What is the mathematical situation
MrMuchimi

Answer:

There is no situation given...

8 0
3 years ago
The gas mileage for a certain model of car is known to have a standard deviation of 6 mi/gallon. A simple random sample of 36 ca
xxTIMURxx [149]

The 98% confidence interval for the mean gas mileage for this car model is (26.07,30.73).

Confidence intervals are defined as a range of values with a known chance that a parameter's value falls inside them.

The confidence interval of statistical data is computed using the formula:

(\overline{x} - Z\frac{\sigma }{n},\overline{x} + Z\frac{\sigma }{n})

where \overline{x} is the mean, Z is the Z-score corresponding to the confidence interval, σ is the standard deviation, and n is the sample size.

In the question, the sample size (n) = 36, the mean of the sample (\overline{x}) = 28.4 mi/gallon, the standard deviation (σ) = 6 mi/gallon.

The confidence interval given to us is 98%.

Z-score corresponding to this (Z) = 2.33.

Thus, the confidence interval can be calculated as:

(28.4 - 2.33{6/√36},28.4 + 2.33{6/√36})

= (28.4 - 2.33,28.4 + 2.33)

= (26.07,30.73).

Thus, the 98% confidence interval for the mean gas mileage for this car model is (26.07,30.73).

Learn more about constructing confidence intervals at

brainly.com/question/17030704

#SPJ4

5 0
2 years ago
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