The probability that a 2 or 3 is rolled at least once is 0.14.
<h3>
Probability of not rolling a 2 or 3 in a single die roll of two dice</h3>
when a six die is rolled once there is 11/12 probability of not rolling 2 or 3.
rolling a six sided die two times, p(2 or 3)' = 11/12
rolling a six sided die four times, p(2 or 3)' = (11/12)² = 121/144
the probability that a 2 or 3 is rolled at least once is calculated as follows;
P = 1 - p(2 or 3)'
P = 1 - 121/144
P = 20/144
P = 0.14
Thus, the probability that a 2 or 3 is rolled at least once is 0.14.
Learn more about probability here: brainly.com/question/24756209
#SPJ4
When we solve for y, we want to isolate y by itself. To do so in this equation, we can divide both sides of the equation by 62...
y = 434/62 = 7
Answer:
-6x(-7)( negative and negative = positive)
Step-by-step explanation:
-6x4= -24
-6x(-7) = 42
-3x8= -24
6x(-4) = -24
Here let us first write the value of each number:
6 thousands means 6*1000=6000.
9 hundreds means 9*100=900.
12 tens means 12*10 =120
10 ones means 10*1 =10
3 tenths means 3/10 =0.3
Now we just have to add all these values to get the final number.
adding 6000 + 900 +120 +10 +0.3 = 7030.3
So the final number is 7030.3
Answer is D.
28:44 is the ratio but you have to simplify it. Divide both by 4. 28 divided by 4 = 7; 44 divided by 4 = 11
