I’m not sure abt 21 but 22 is the second one and the 4th one. So 2,4.
Answer:
Step-by-step explanation:
Since the amount of soft drink dispensed into a cup is normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = amount in ounce of soft drink dispensed into cup.
µ = mean amount
σ = standard deviation
From the information given,
µ = 7.6oz
σ = 0.4 oz
a) The probability that the machine will overflow an 8-ounce cup is expressed as
P(x > 8) = 1 - P(x ≤ 8)
For x = 8,
z = (8 - 7.6)/0.4 = 1
Looking at the normal distribution table, the probability corresponding to the z score is 0.84
P(x ≤ 8) = 1 - 0.84 = 0.16
b) P(x< 8) = 0.84
c) when the machine has just been loaded with 848 cups, the number of cups expected to overflow when served is
0.16 × 848 = 136 cups
Answer: (a) 
(b) 
Step-by-step explanation:
(a) P( Bill hitting the target) = 0.7 P( Bill not hitting the target) = 0.3
P( George hitting the target) = 0.4 P(George not hitting the target) = 0.6
Now the chances that exactly one shot hit the target is = 0.7 x 0.6 + 0.4 x 0.3
= 0.54
Chances that George hit the target is = 0.4 x 0.3 = 0.12
So given that exactly one shot hit the target, probability that it was George's shot = 
= .
(b) The numerator in the second part would be the same as of (a) part which is 0.12.
The change in the denominator will be that now we know that the target is hit so now in denominator we include the chance of both hitting the target at same time that is 0.4 x 0.7 and the rest of the equation is same as above i.e.
Given that the target is hit,probability that George hit it = 
= =
Answer:
$95
Step-by-step explanation:
you had to subtract the two numbers .
Answer: left a units, down b units
Step-by-step explanation:
