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wel
3 years ago
9

Annie is creating a stencil for aher artwork using a coorindate plan. THe beginning of the edge of the stencil falls at (-1,2),

She wants to align an important detail on the left edge of her stencil at (2,1).
Mathematics
1 answer:
nadya68 [22]3 years ago
5 0

Answer:

The correct option is: (0.5, 1.5)

Step-by-step explanation:

I will use the notation (x, y) to solve this.

The start is at (-1, 2)

And the point (2,1) is at 1:2 of the point where she wants to finish the stencil. (so the actual end of the stencil is at half the distance between these two points)

First, we calculate the distance between these two points.

Now, we assume that the line is a straigth line, se we can suppose that there is a linear equation for this line, we can get the slope of it as:

s = (y2 - y1)/(x2 -x1)

in this case

s = (1 - 2)/(2 - (-1)) = -1/3

The slope os s = -1/3

then our line is:

y(x) = -1/3*x + b

and we know that when x = -1, we have:

y(-1) = 2 = -1/3*-1 + b = 1/3 + b

b = 2 - 1/3 = 5/3.

y(x) = -1/3*x + 5/3

then, knowing that this is a linear relation, then if we want the half point between the two given ones, we need to valuate our linear relationship in the middle of the two x values that we have.

x = -1 and x = 2.

To calculate the middle value, we calculate the difference between these numbers and we divide it by 2, and then we add that number to the smaller (in this case -1)

x0 = -1 + (2 - (-1))/2  = -1 + 1.5 = 0.5

Now we evaluate our linear equattion in this point:

y(0.5) =  -1/3*0.5+ 5/3 = 1.5

The correct option is: (0.5, 1.5)

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Carter draws one side of equilateral △PQR on the coordinate plane at points P(-3,2) and Q(5,2). Which ordered pair is a possible
Law Incorporation [45]

Step-by-step explanation:

Hey, there!!!

Let me simply explain you about it.

We generally use the distance formula to get the points.

let the point R be (x,y)

As it an equilateral triangle it must have equal distance.

now,

let's find the distance of PQ,

we have, distance formulae is;

pq =    \sqrt{( {x2 - x1)}^{2}  + ( {y2 - y1)}^{2} }

or \:  \sqrt{( {5  + 3)}^{2} + ( {2 - 2)}^{2}  }

By simplifying it we get,

8

Now,

again finding the distance between PR,

pr = \sqrt{( {x2 - x1}^{2}  + ( {y2 - y1)}^{2} }

or,

\sqrt{( {x + 3)}^{2}  + ( {y - 2)}^{2} }

By simplifying it we get,

=  \sqrt{ {x}^{2} +  {y}^{2} + 6x  -  4y + 13  }

now, finding the distance of QR,

qr =  \sqrt{( {x - 5)}^{2} + ( {y - 2)}^{2}  }

or, by simplification we get,

\sqrt{ {x}^{2} +  {y}^{2}  - 10x - 4y + 29 }

now, equating PR and QR,

\sqrt{ {x}^{2} +  {y}^{2}  + 6x  -  4y  + 13}  =  \sqrt{ {x}^{2}  +  {y}^{2} - 10x - 4y + 29 }

we cancelled the root ,

{x}^{2} +  {y}^{2} + 6x - 4y + 13 =  {x}^{2}   +  {y}^{2}   -10x - 4y + 29

or, cancelling all like terms, we get,

6x+13= -10x+29

16x=16

x=16/16

Therefore, x= 1.

now,

equating, PR and PQ,

\sqrt{ {x}^{2} +  {y}^{2}  + 6x - 4y + 13 }  =  8}

cancel the roots,

{x}^{2} +  {y}^{2}   + 6x - 4y + 13  = 8

now,

(1)^2+ y^2+6×1-4y+13=8

or, 1+y^2+6-4y+13=8

y^2-4y+13+6+1=8

or, y(y-4)+20=8

or, y(y-4)= -12

either, or,

y= -12 y=8

Therefore, y= (8,-12)

by rounding off both values, we get,

x= 1

y=(8,-12)

So, i think it's (1,8) is your answer..

<em>Hope it helps</em><em>.</em><em>.</em><em>.</em>

3 0
3 years ago
What is the equation of the line that passes through (-2, 2) and (1, -4)?
poizon [28]

Answer:

y = - 2x - 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁  = (- 2, 2) and (x₂, y₂ ) = (1, - 4)

m = \frac{-4-2}{1+2} = \frac{-6}{3} = - 2, thus

y = - 2x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (- 2, 2), then

2 = 4 + c ⇒ c = 2 - 4 = - 2

y = - 2x - 2 ← equation of line

3 0
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Bill hikes 8 miles in 3 hours. At this rate. how many miles will he hike after 2 hours?
exis [7]

Answer:

5 1/3 miles

Step-by-step explanation:

We can use a ratio to solve

8 miles      x miles

------------ = --------

3 hours         2 hours

Using cross products

8*2 = 3x

16 = 3x

Divide by 3

16/3 = 3x/3

5 1/3 miles =x

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Because x was *3 you had to y*3 which is 
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