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Delicious77 [7]
2 years ago
15

Find the sum of (x²+3xy+y²)+(x³+3x²y+2xy²+y³)​

Mathematics
1 answer:
victus00 [196]2 years ago
5 0
X
3
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3
x
2
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2
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y
2
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y
3
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2
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3
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2
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If the graph of the equation y=(x+2)^2 is reflected with respect to the y-axis, what is the equation of the resulting graph?
alexandr1967 [171]

Answer:

Is important to remember that the reflection of the point (a,b) across  the y-axis is the point (-a,b).

Our original equation is y= (x+2)^2

And after the reflection respect x we got:

y= (-x+2)^2

Step-by-step explanation:

Is important to remember that the reflection of the point (a,b) across  the y-axis is the point (-a,b).

Our original equation is y= (x+2)^2

And after the reflection respect x we got:

y= (-x+2)^2

7 0
3 years ago
You own an accessories store, and sales last month were $24,000. You had $3,500 in discounts and $975 in returns.
Len [333]

Answer:

The net sales for last month were <u>$19,525</u>.

Step-by-step explanation:

Given:

Last month sales were $24,000.

Discounts is $3,500 and $975 in returns.

Now, to get the net sales for last month.

So, we deduct the discount:

<em>Sales - discounts</em> = \$24,000 - \$3,500 =\$20,500.

Then, we deduct the returns from the remaining amount:

<em>Sales after discounts - returns</em> = \$20,500 - \$975

                                                   = \$19,525.

Therefore, the net sales for last month were $19,525.

7 0
3 years ago
Help!! Lots of points
murzikaleks [220]

\frac{ {5}^{2} }{ {2}^{2} }  =  {( \frac{5}{2}) }^{2}
Since they are both squared.

Evaluating 5^2 and 2^2 and finding the quotient also works.

\frac{ {5}^{2} }{ {2}^{2} } =  \frac{5 \times 5}{2 \times 2}   =  \frac{25}{4}  = 6.25\\  \frac{ {5}^{2} }{ {2}^{2} }  =  {( \frac{5}{2} )}^{2}  = 2.5 \times 2.5 = 6.25
The third option, "Evaluate 5^2 and 2^2 ...," and the last option, "Rewrite the expression as (5/2)^2 ...," are the correct choices.
3 0
3 years ago
Read 2 more answers
NEED HELP ASAP!
ziro4ka [17]
We see it is the y terms squared so it opens left or right

in form
(y-k)^2=4(p)(x-h)
vertex is (h,k)
and p is distance from focus to vertex, also distance from vertex to directix
if p>0, then it opens to the right and dirextix is to the left of vertex
if p<0, then it opens to the left and directix is tothe right of vertex


so
(y-1)^2=4(4)(x-(-3))
vertex is (-3,1)
4>0 so dirextix is to left of vertex
left is in x direction
-3-4=-7
directix is x=-7
4 0
2 years ago
Homework Progress
Alborosie
I think answer should be c. Please give me brainlest let me know if it’s correct or not okay thanks bye
7 0
3 years ago
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