Hello,
f(x)-f(a)= -3x²-5x+1-(-3a²-5a+1)=-3(x²-a²)-5(x-a)=-3(x-a)(x+a)-5(x-a)
=-(x-a)(3(x+a)+5)
=-(x-a)(3x+3a+5)
lim (f(x)-f(a))/(x-a)=- lim (3x+3a+5)=3a+3a+5=-6a-5
if a=1==>-6*1-5=-11
Otherwise
f'(x)=-6x-5
f'(1)=-6-5=-11
at point(1,-7)
Answer:
32
hope this helps
have a good day :)
Step-by-step explanation:
I don't know what your looking for, so be more specific, but I'm assuming your solving for x, so that's would be
x = -1
Answer
<h2>16 - 4</h2><h2 />
Step-by-step explanation:
If you subtract the amounts of the other flowers you end up with four meaning there are four daises in the vase.
<em>Good Luck With Your Work!</em>
<em></em>
<em></em>
<h3>
Please let me know if I am incorrect!</h3>
Step-by-step explanation:
First, find the zeroes of the parabola
So the zeroes or where the curve crosses the x axis is at 4 and -3.
Now, we take the derivative of the function.
Plug in -3, and 4 into the derivative function
So at x=-3, our slope of the tangent line is -7 and must pass through (-3,0). So we use point slope formula.
At x=4, our slope of tangent line is 7, and pass through (4,0) so
So the equations of tangent is