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mash [69]
3 years ago
6

The processor in Q1 above is converted into an 8-stage pipeline, similar to the one discussed on slide 8 of lecture 16. It takes

125 ps to navigate the circuits in each stage. Assume that latches do not introduce a noticeable delay overhead.1. What is the clock speed of this processor? 2. What is the CPI of this processor, assuming that every load/store instruction finds its instruction/data in the instruction or data cache, and there are no stalls from data/control/structural hazards? 3. What is the throughput of this processor (in billion instructions per second)?
Computers and Technology
1 answer:
Nadusha1986 [10]3 years ago
3 0

Answer:

1000/125 billion instructions per second.

Explanation:

All the stages take 125ps and latch time was outlooked.

The clock speed would be the highest stage time in all 5 stages. Here all are same clock speed it would be 125ps only.

throughput = 1/cycle time so ⇒ 1/125 instructions/ps

Since we want it in billion instructions per second so we have to multiply with 10⁻⁹ /10⁻¹² then the result is 1000/125 billion instructions per second.

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Create a recursive method, a method that calls itself, that returns the number of vowels that appear in any string given. Keep i
kvv77 [185]
<h2>Answer:</h2>

//Define the method as noOfVowels

   //Let it receive the string to be checked as argument

   public static int noOfVowels(String string){

   

       //Check the length of the string

       

       //If it is less than 1, then it is an empty string

       //Hence return 0

       if(string.length() < 1){    

           return 0;

       }

       

       //Else,

       else{

           //get the character at the first position in the string

           //and convert it to a lower case

           char x = string.toLowerCase().charAt(0);

           //Check if the character is a vowel

           if (x == 'a' || x == 'e' || x == 'i' || x == 'o' || x == 'u'){

               //if it is a vowel, add 1 to a recall of the method.

               //But this time, call the method with  

               //the string excluding the first character.

               //i.e the substring of the string starting at index 1 rather than 0

               return 1 + noOfVowels(string.substring(1));

           }

           

           else {

               //If it is not a vowel, just recall the method with

               //the string excluding the first character

               //i.e the substring of the string starting at index 1 rather than 0

               return noOfVowels(string.substring(1));

           }

       }

   }

   

<h2>Explanation:</h2><h2></h2>

The code has been written in Java and it contains comments explaining every part of the code. Please go through the comments carefully.

The actual lines of code have been written in bold face to distinguish them from comments.

The code is re-written without comments as follows;

   public static int noOfVowels(String string){

   

       if(string.length() < 1){    

           return 0;

       }

       

       else{

           char x = string.toLowerCase().charAt(0);

           if (x == 'a' || x == 'e' || x == 'i' || x == 'o' || x == 'u'){

               return 1 + noOfVowels(string.substring(1));

           }

           

           else{

               return noOfVowels(string.substring(1));

           }

       }

   }

   

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