Answer:
import sys, time
from os import walk, remove
from os.path import exists, join, getsize, getctime
file_counter = [ ]
folder_name, file_size = argv
isExist = exists( folder_name )
if folder_name == True:
for root, folder, files in walk( folder_name ):
for file in files:
if getsize( join ( root, file ) ) >= file_size:
file_log = [ ]
file_log.append( file )
file_log.append( join ( root, file) )
file_log.append( time.ctime( getctime( file ) ) )
file_counter.append( file_log )
else:
remove ( join ( root, file ) )
Explanation:
The python script above output the filename, size and file creation date of any folder passed to it.
Well it is a very simple process all you do is open adobe photoshop and then put your picture in there then you go to your power point and go to file then new go to custom background got to photoshop chance the dimensions to your liking and boom done
Hello <span>Imansimmons1412
</span><span>
Answer: </span>Data redundancy occurs when the same data is duplicated in multiple files of a database.
Hope This Helps
-Chris
Hi!
Well, this isn't exactly a question - but rather just a request. However, I'm going to attempt to try and <em>describe </em>to you how to approach this problem, instead of just writing the code for you and sending you on your way.
So, what's our general base goal here? We want to take a string into a function, and then print it out backwards. Seems simple enough!
Right away, we already have an idea how to set this code up. We need a main method which will call <em>PrintBackwards(), </em>which will have to take a parameter of type string.
This would look something like <em>PrintBackwards(string baseString). </em>Inside this method, we'd have to do something so we can see each character in this string and then store it in a new string.
I encourage you to try and tackle this on your own, but I can give you an idea. We can have a new valueless variable called reversedString, which will store our baseString but backwards.
We could try looping through the baseString for each character it possesses, and then keep adding onto our reversedString by doing something like +=. What I mean, is we'd access the very last index of baseString, and then keep appending characters into it.
So our loop would look something like <em>for(int i = baseString.length; i > 0; i--) {}.
</em>I haven't used C++ in awhile, so you'll have to find the specific syntax requirements. But with that loop, i represents the index of each character in baseString. It starts with the last index, and keeps going down in reverse.
<em>
</em>Inside our loop, we could do something like reverseString += baseString.index(i); Again, I don't remember the specific syntax - so you'll have to do this on your own.
<em>
</em>Hopefully, this helps! =)<em>
</em>
