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geniusboy [140]
3 years ago
7

What can you do to improve your own digital wellness?

Computers and Technology
2 answers:
julsineya [31]3 years ago
4 0
Update your passwords frequently, delete unused accounts, and be diligent about who and what you give your most personal information to. Invest in tech that fits your lifestyle without offering further distractions.
sattari [20]3 years ago
4 0
Take frequent breaks, limit what you are exposed to, go through what you follow/subscribe to regularly, learn how to spot fake things.
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Icon view, list view, and details view are all common views provided by which kind of program?
RideAnS [48]
The standard program that uses common views such as the icon view, list view, and details view would be the program known as "File Explorer" (Windows) or "Finder" (Mac). This program uses all the views to make selecting and tracking down certain files a much more painless and easier process to complete.

Hope this helps and good luck! :)
6 0
4 years ago
Read 2 more answers
Write a program that reads in an integer value for n and then sums the integers from n to 2 * n if n is nonnegative, or from 2 *
devlian [24]

Answer:

Following are the program in c++

First code when using for loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

for(i=n; i<=(2*n); i++)

{

sum1+= i;

}

}

else //  check if n  is negative

{

for(i=(2*n); i<=n; i++)

{

sum1+= i;

}

}

cout<<"The sum is:"<<sum1;

return 0;

Output

Enter the number: 1

The sum is:3

second code when using while loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

else //  check if n  is negative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

cout<<"The sum is:"<<sum1;

return 0;

}

Output

Enter the number: 1

The sum is:3

Explanation:

Here we making 2 program by using different loops but using same logic

Taking a user input in "n" variable.

if n is nonnegative then we iterate the loops  n to 2 * n and storing the sum in "sum1" variable.

Otherwise iterate a loop  2 * n to n and storing the sum in "sum1" variable.  Finally display  sum1 variable .

4 0
3 years ago
Where might an awareness of Greek word origins be helpful?
devlian [24]
Greek word origins be helpful at a doctors offics
8 0
3 years ago
What is the error in the following pseudocode?
kykrilka [37]
I do not know the answers sorryy
4 0
2 years ago
Add me on xbox ahaha craig#6822 this is also just for points
Monica [59]

Answer:

sadly i dont have one:(

4 0
3 years ago
Read 2 more answers
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