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LenaWriter [7]
4 years ago
5

How do you solve this ? Please show work.

Mathematics
2 answers:
ioda4 years ago
7 0
1.for x it's 2x+5y=-1 you just do -5y on each side so you get 2x=-5y-1 then you divide it by 2 and it's x=-5/2-1/2
tekilochka [14]4 years ago
5 0
Y=-1, x=2

2x+5y=-1
x=-2y

2(-2y)+5y=-1
-4y+5y=-1
y=-1


x+2y=0
x-2=0
x=2
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The circle below is centred at point (2,-1) and has a radius of length 3 what is its equation ?
NeTakaya

Answer:

Option C

Step-by-step explanation:

The standard form of equation of a cirle is:

(x-h)^2+ (y-k)^2=r^2

In the given question as the point is given and the radius of circle is given:

So,

(h,k)=(2,-1)

and

r=3

Here,

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Putting the values of h,k and r in standard form

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(x-2)^2+ (y+1)^2=(3)^2

So the equation of circle is:

(x-2)^2+ (y+1)^2=9(3)^2

Option C is the correct answer ..

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3 years ago
Plz help first to answer gets 50 points
djverab [1.8K]
D is the correct answer bc the 3’s continue forever
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Answer:

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Step-by-step explanation:

solve for x

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no they are not equivalent

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