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puteri [66]
3 years ago
15

Look at the graph below. Which of the following best represents the slope of the line? A. -3 B. - 1 3 C. 1 3 D. 3

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
3 0

Answer and Explanation:

The line seems to pass trough the points (0,6) and (-3,4).

Slope is: m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{4-6}{-3-0} =\frac{-2}{-3} =\boxed{\frac{2}{3}}

The slope of the line should be \frac{2}{3}.

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<h2>Answer:</h2>

The decimal point should be placed between digits 9 and 7 in the dividend. i.e the dividend becomes 269.7

<h2>Step-by-step explanation:</h2>

Dividend = 26.97       [numerator]

Divisor = 6.3               [denominator]

If 26.97 ÷ 6.3 is written in long division form so that the divisor is written as a whole number, we have the following;

(i)First convert the divisor to a whole number by multiplying by 10 i.e

6.3 x 10 = 63

(ii) Since the divisor (denominator) has been multiplied by 10, to make sure the division expression stays the same, we need to multiply the dividend(numerator) too by 10. i.e

26.97 x 10 = 269.7

(iii) The division expression then becomes;

269.7 ÷ 63

Therefore, the decimal point should be placed between digits 9 and 7 in the dividend.

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Answer:

Part 1) m∠1 =(1/2)[arc SP+arc QR]

Part 2) PR^{2} =PS*PT

Part 3) PQ=PR

Part 4) m∠QPT=(1/2)[arc QT-arc QS]

Step-by-step explanation:

Part 1)

we know that

The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite.

we have

m∠1 -----> is the inner angle

The arcs that comprise it and its opposite are arc SP and arc QR

so

m∠1 =(1/2)[arc SP+arc QR]

Part 2)

we know that

The <u>Intersecting Secant-Tangent Theorem,</u> states that the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.

so

In this problem we have that

PR^{2} =PS*PT

Part 3)

we know that

The <u>Tangent-Tangent Theorem</u>  states that if from one external point, two tangents are drawn to a circle then they have equal tangent segments

so

In this problem

PQ=PR

Part 4)

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

In this problem

m∠QPT -----> is the outer angle

The arcs that it encompasses are arc QT and arc QS

therefore

m∠QPT=(1/2)[arc QT-arc QS]

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