Question

(X) = \frac{(X-3)(X+1)}{(X+3)}" alt="F(X) = \frac{(X-3)(X+1)}{(X+3)}" align="absmiddle" class="latex-formula">
What is the:
Domain:
Holes:
VA:
HA:
OA: Roots:
Y-Intercepts:

Answer 1

Answer:

Step-by-step explanation:

Given function is

$f(x)=\frac{(x-3)(x+1)}{(x+3)}$

Domain of the function: (-∞,-3)∪(-3,∞) x | x ≠ -3

Holes: none. No common factors in numerator and denominator

VA: x = -3 as denominator is (x+3)

HA: No horizontal asymptote because degree of the denominator is less than numerator

OA: Roots are x = 3, -1 [(x-3) and (x+1) are the factors]

Y-Intercept: (0, -1) (by putting x = 0 in the given function)