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3 years ago

Which expression represents the multiplication inverse 2/7 ?

Mathematics

1 answer:

bulgar [2K]3 years ago

5 0

Answer:

Step-by-step explanation:

The multiplicative inverse of a number n is $\frac{1}{n}$ and

n × $\frac{1}{n}$ = 1

Hence

given $\frac{2}{7}$

The multiplicative inverse = $\frac{1}{\frac{2}{7} }$ = $\frac{7}{2}$

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What is the value of a when we rewrite 8^x as a^-x/9

Andre45 [30]

Answer:

$a = \frac{1}{134217728}$

Step-by-step explanation:

Given

$8^x = a^{-x/9}$

Required

Find a

Take log of both sides

$log(8^x) = log(a^{-x/9})$

Apply law of logarithm

$x\ log(8) = (-x/9) log(a)$

Divide both sides by a

$log(8) = -\frac{1}{9} log(a)$

Multiply both sides by -9

$-9\ log(8) = log(a)$

Apply law of logarithm

$log(8^{-9}) = log(a)$

Cancel out log

$8^{-9} = a$

Rewrite as:

$a = 8^{-9}$

Apply law of indices

$a = \frac{1}{8^9}$

$a = \frac{1}{134217728}$

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3 years ago

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This is easier to understand with a picture...

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