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2 years ago

11

Which expression represents the multiplication inverse 2/7 ?

1 answer:

bulgar [2K]2 years ago

5 0

Answer:

C

Step-by-step explanation:

The multiplicative inverse of a number n is $\frac{1}{n}$ and

n × $\frac{1}{n}$ = 1

Hence

given $\frac{2}{7}$

The multiplicative inverse = $\frac{1}{\frac{2}{7} }$ = $\frac{7}{2}$

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Archy [21]

Answer:

your answer is below c:

Step-by-step explanation:

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3 years ago

Of the numbers listed below, which are not multiples of 4? 2,4,7,8,12,15,19,24,34

sashaice [31]

7,15,19,34 are not multiples of four. to find this answer out just divide four into them.

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2 years ago

Read 2 more answers

triangle has sides measuring 2 inches and 7 inches If x represents the length in inches of the third side which inequality gives

il63 [147K]

We know that
The sum of the lengths of any two sides of a triangle is greater than the length of the third side (<span>Triangle Inequality Theorem)
so
inequality 1
</span> $(2+7) \ \textgreater \ x \\ 9 \ \textgreater \ x \\ x \ \textless \ 9 in$
<span>
inequality 2
</span> $(x+2) \ \textgreater \ 7 \\ x \ \textgreater \ 7-2 \\ x \ \textgreater \ 5 in$
<span>
the answer is
</span> $5 in \ \textless \ x \ \textless \ 9 in$ <span>
</span>

6 0

2 years ago

Two angles are complementary. The larger angle is 36 more than the smaller angle. What is the measure of the larger angle?

iren [92.7K]

Answer:

The largest angle is 63

Step-by-step explanation:

Shows that one is 36 degrees larger: 63 - 36 = 27

Shows that the angles are complementary/Their sum is 90: 27 + 63 = 90

6 0

2 years ago

An equation of an ellipse is given. y2 = 1 − 3x2 (a) Find the vertices, foci, and eccentricity of the ellipse. vertex (x, y) = (

oksian1 [2.3K]

Answer:

Step-by-step explanation:

Given

$y^2=1-3x^2$

$3x^2+y^2=1$

$\frac{x^2}{(\frac{1}{\sqrt{3}})^2}+\frac{y^2}{1}=1$

therefore it is a vertical ellipse

thus a=1

$b=\frac{1}{\sqrt{3}}$

eccentricity of Ellipse

$e^2=1-\frac{b^2}{a^2}$

$e^2=1-\frac{1}{(\sqrt{3})^2}$

$e^2=1-\frac{1}{3}$

$e^2=\frac{2}{3}$

$e=\sqrt{\frac{2}{3}}$

Focii are $(0,ae)$ and $(0,-ae)$

$ae=1\times \sqrt{\frac{2}{3}}$

thus focii are $(0,\sqrt{\frac{2}{3}})$ & $(0,-\sqrt{\frac{2}{3}})$

(b) Length of major axis $=2a=2\times 1$

length of minor axis $=2b=2\times \sqrt{\frac{2}{3}}=2\cdot \sqrt{\frac{2}{3}}$

8 0

2 years ago