Use your SOH CAH TOA functions to find the missing legs. Do Sin(53.1) and that is equal to opposite (PU) over hypotenuse (UG) so to solve for the PU leg just set up an equation that says sin(53.1)=PU/36 so then you can just multiply the 36 over and that gives you the leg. To find PG do adjacent over hypotenuse so Cosine, cos(53.1)=PG/36 and again just multiply over the 36 and that gives you PG
Answer:
b : $0.22 on edg.
Step-by-step explanation:
1 inch =2.5cm
lenght =30.25×2.5=75.625cm
width = 21×2.5=52.5cm
area of painting = 75.625×52.5=3970.3125cm²
We have that
scale factor=1 in/2.5 miles
<span>the actual area of a lake is 12 square miles
</span>we know that
[area on the map]=[scale factor]²*[area actual]
[area on the map]=[1/2.5]²*[12]-----> 1.92 in²
the answer is
1.92 in²
DEF= 6 ft^2
A= 1/2*b*h
Plug in what you know.
6= 1/2*4*h
Multiply like terms.
6=2*h
Divide 2 on both sides.
3=h
If the base of ABC= 12
12/4=3
3*3=9
A= 1/2*b*h
A= 1/2*12*9
A= 1/2*84
A= 42
The area of ABC is 42 ft^2
I hope this helps!
~kaikers
