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2 years ago

70 POINTS QUESTION ATTACHED (actually attached this time lol)

Mathematics

2 answers:

hram777 [196]2 years ago

8 0

Answer:

sqrt1/25 sqrth^^2

1/5 h

Step-by-step explanation:

omeli [17]2 years ago

6 0

Answer:

(1/5 h)^2

Step-by-step explanation:

1/25 h^2

To make this a perfect square we need to take the square root and then square it

(sqrt(1/25 h^2))^2

we know that sqrt(ab) = sqrt(a) sqrt(b)

(sqrt(1/25) sqrt(h^2))^2

(1/5 h)^2

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Answer:

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2 years ago

Aubrey finished 2/9 of a project on Monday and 1/4 of the project of Tuesday. How much of the project has Aubrey completed?

riadik2000 [5.3K]

Answer:

17/36

Step-by-step explanation:

We have to find a common denominator, so the first common denominator for 4 and 9 is 36. 9x4=36, so we multiply 2 by 4, which equals 8. 4x9-36, so we multiply the 1 by 9, and get 9. Then we add the numerators, 8 and 9, and get 17. So it's 17/36

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2 years ago

Jake needs to buy 120beverages for a party. What equation, in standard form, determines the number x of 8-packs of juice and the

kaheart [24]

8x+12y=120

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-------------------------------

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3 0

2 years ago

How is this worked out ? im confused.

Rudik [331]

Answer:

From the given ratio for $tan\theta=\frac{4}{5}$ we found the values are

$sin\theta=4$

$cos\theta=5$

$csc\theta=\frac{1}{4}$

$sec\theta=\frac{1}{5}$

$cot\theta=\frac{5}{4}}$

Step-by-step explanation:

Given the ratio for $tan\theta=\frac{4}{5}$

We have to find the rest of trignometric functions:

$tan\theta=\frac{4}{5}\hfill (1)$

$tan\theta$ can be written as

$tan\theta=\frac{sin\theta}{cos\theta}\hfill (2)$

Comparing equations (1) and (2) we get

$tan\theta=\frac{sin\theta}{cos\theta}=\frac{4}{5}$

$\frac{sin\theta}{cos\theta}=\frac{4}{5}$

Equating the coressponding numerator and denominator respectively

Therefore $sin\theta=4$ and $cos\theta=5$

We can find $csc\theta$

$csc\theta=\frac{1}{sin\theta}$

$=\frac{1}{4}$ (since $sin\theta=4$ )

$csc\theta=\frac{1}{4}$

We can find $sec\theta$

$sec\theta=\frac{1}{cos\theta}$

$=\frac{1}{5}$ (since $cos\theta=5$ )

$sec\theta=\frac{1}{5}$

To find $cot\theta$ :

$cot\theta=\frac{1}{tan\theta}$

$=\frac{1}{\frac{4}{5}}$

$=1\times \frac{5}{4}$

$=\frac{5}{4}}$

$cot\theta=\frac{5}{4}}$

7 0

3 years ago