The answer is {1, 2, 10, 50, 75}. It has a median of 10 and a mean larger than 10
If A and B are equal:
Matrix A must be a diagonal matrix: FALSE.
We only know that A and B are equal, so they can both be non-diagonal matrices. Here's a counterexample:
![A=B=\left[\begin{array}{cc}1&2\\4&5\\7&8\end{array}\right]](https://tex.z-dn.net/?f=A%3DB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%262%5C%5C4%265%5C%5C7%268%5Cend%7Barray%7D%5Cright%5D)
Both matrices must be square: FALSE.
We only know that A and B are equal, so they can both be non-square matrices. The previous counterexample still works
Both matrices must be the same size: TRUE
If A and B are equal, they are literally the same matrix. So, in particular, they also share the size.
For any value of i, j; aij = bij: TRUE
Assuming that there was a small typo in the question, this is also true: two matrices are equal if the correspondent entries are the same.
1 meter is greater then 83 cm Because if you divide it will be 0.83 and the differences will be 0.17
Answer:
The Pythagorean identity states that

Using that we can rewrite the left denominator as:

Which can be factored as

The numerator we can expand as:

On the right hand side, let's multply numerator and denominator with (1 - sin t):
The total formula then becomes:

There you go... left and right are equal.
(g₀f)(x)=g(f(x))
=g(2x-2)
=5(2x-2)^2-3
=5(4x^2-8x+4)-3
=20x^2-40x+17