In △BCD, BP=15 cm.

Mathematics

2 answers:

Phantasy [73]3 years ago

6 0

we know that

The centroid is the point where all three medians intersect and divides each median in a ratio of $2:1$ . Is described as the triangle's center of gravity.

In this problem

C-Q, B-P and D-R ------> are medians

The point X is the centroid of the triangle BCD

$BX=\frac{2}{3}BP$

we have

$BP=15\ cm$

substitute

$BX=\frac{2}{3}(15)=10\ cm$

therefore

<u>the answer is</u>

$BX=10\ cm$

MAXImum [283]3 years ago

5 0

The answer is 10.

I PERSONALLY guessed it because it looks like BX is 10 and XP is 5 which is 15. (But I don't recommend always doing this because you might make a mistake when it comes to testing.)

HOWEVER: I confirmed it afterwards. The answer is still 10.

You might be interested in

Evaluate ,where e is the solid that lies between the cylinders x^2+y^2=1 and x^2+y^2=16, above the xy-plane, and below the plane

MA_775_DIABLO [31]

Assuming you're just computing the volume, i.e.

$\displaystyle\iiint_E\mathrm dV$

we should convert to cylindrical coordinates first, setting

$\begin{cases}x=r\cos\theta\\y=r\sin\theta\\z=\zeta\end{cases}$

so that the volume is given by

$\displaystyle\iiint_E\mathrm dx\,\mathrm dy\,\mathrm dz=\int_{\theta=0}^{\theta=2\pi}\int_{r=1}^{r=4}\int_{\zeta=0}^{\zeta=r\sin\theta+4}r\,\mathrm d\zeta\,\mathrm dr\,\mathrm d\theta$

which has a value of $60\pi$ .