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goldenfox [79]
3 years ago
9

Naming properties- 6(x-4)=6x-24

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
6 0
I hope this helps you



6x-24=6x-24



0=0
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Integrate the following. ∫<img src="https://tex.z-dn.net/?f=5x%5E%7B4%7D%20dx" id="TexFormula1" title="5x^{4} dx" alt="5x^{4} dx
Vadim26 [7]

Answer:

\displaystyle D)  {x}^{5}  +  \rm C

Step-by-step explanation:

we would like to integrate the following Integral:

\displaystyle \int 5 {x}^{4} \, dx

well, to get the constant we can consider the following Integration rule:

\displaystyle \int c{x} ^{n}  \, dx  =  c\int  {x}^{n}  \, dx

therefore,

\displaystyle 5\int  {x}^{4} \, dx

recall exponent integration rule:

\displaystyle \int {x} ^{n}  \, dx  =  \frac{ {x}^{n + 1} }{n + 1}

so let,

  • n = 4

Thus integrate:

\displaystyle  =  5\left( \frac{ {x}^{4+ 1} }{4 +  1}  \right)

simplify addition:

\displaystyle  =  5\left( \frac{ {x}^{5} }{5}  \right)

reduce fraction:

\displaystyle  =  {x}^{5}

finally we of course have to add the constant of integration:

\displaystyle  \boxed{ {x}^{5}  +  \rm C}

hence,

our answer is D)

7 0
2 years ago
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2x + y = 13<br> What y????
hoa [83]

Answer:

2(5) + 3 = 13

Step-by-step explanation:

x=5

y=3

2x+y=13

2(5)+3=13

10 +3 =13

8 0
2 years ago
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If you have a mass of 55g that has a volume of 11 ml, what is the density?
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Answer:

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Step-by-step explanation:

D=M/V

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A negative cannot be a root, 8= 2.4
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2 years ago
you go to school is a college town. you know that there are 2000students enrolled in the school, but you don't know the populati
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If you ask 100 people and 60 say they are students, then you would assume that 60/100 people in town as a whole are students.  To estimate the non-student population, you would infer that the other 40 are not students, thus making the non-student to student ratio 40:60 or 2:3 when simplified.  This means that for every 2 non-students, there are 3 students.  If we multiply 2000 by this 2:3 ratio, we would see that 2/3*2000 = the non-student population.The non-student population is estimated at 1,333.
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