The average rate of change is given by [f(b) - f(a)]/(b - a), where a and b represent the interval [a, b].
Let a = -2
Let b = -1
[(-1)^2 + 10 - ((-2)^2 + 10)]/(-1 -(-2))
[1 + 10 - (4 + 10)]/(-1 + 2)
[1 + 10 -4 -10]/(1)
[1 - 4]/(1)
-3/1
Answer: -3
Answer:
(x − 2) = 3
Remove the bracket
x - 2 = 3
Group the constants at one side of the equation
x = 2 + 3
x = 5
Therefore x = 5.00 to 3 significant figures.
Hope this helps
Answer:
(1, 0) and (3, 0)
Step-by-step explanation:
y=2x²-8x+6
x- intercept when y=0
- 2x²-8x+6=0
- x²-4x+4=1
- (x-2)²=1
- x-2=1 ⇒ x= 3
- x-2= -1 ⇒ x= 1
Answer:
60
Step-by-step explanation:
You have five exterior choices, then you multiply that by the six interior choices, then multiply the two model choices.
Let c represents the cost of a candy apple and b represents the cost of a bag of peanuts.
Darius can purchase 3 candy apples and 4 bags of peanuts. So his total cost would be 3c + 4b. Darius can buy 3 candy apples and 4 bags of peanuts in $11.33,so we can write the equation as:
3c + 4b = 11.33 (1)
Darius can purchase 9 candy apples and 5 bags of peanuts. So his total cost would be 9c + 5b. Darius can buy 9 candy apples and 5 bags of peanuts in $23.56,so we can write the equation as:
9c + 5b = 23.56 (2)
<span>Darius decides to purchase 2 candy apples and 3 bags of peanuts. The total cost in this case will be 2c + 3b. To find this first we need to find the cost of each candy apple and bag of peanuts by solving the above two equations.
Multiplying equation 1 by three and subtracting equation 2 from it, we get:
3(3c + 4b) - (9c + 5b) = 3(11.33) - 23.56
9c + 12b - 9c - 5b = 10.43
7b = 10.43
b = $1.49
Using the value of b in equation 1, we get:
3c + 4(1.49) = 11.33
3c = 5.37
c = $ 1.79
Thus, cost of one candy apple is $1.79 and cost of one bag of peanuts is $1.49.
So, 2c + 3b = 2(1.79) + 3(1.49) = $ 8.05
Therefore, Darius can buy 2 candy apples and 3 bags of peanuts in $8.05</span>
