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Ket [755]
3 years ago
6

-6q+5.8=23.8 q=3 q=-3 q=1.83 q=4.93 i really need help im stuck i have 3 othere Q but ill figure them out

Mathematics
1 answer:
TEA [102]3 years ago
3 0
The answer to the equation is the second option.
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Help me with this one.
sammy [17]
Pretty sure it's:
25+-8+-3
25+-11
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4 0
3 years ago
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Part A: Create a third-degree polynomial in standard form. How do you know it is in standard form? (5 points)
Svetlanka [38]

Answer:

(See explanation for further details)

Step-by-step explanation:

a) Let consider the polynomial p(x) = 5\cdot x^{3} +2\cdot x^{2} - 6 \cdot x +17. The polynomial is in standards when has the form p(x) = \Sigma \limit_{i=0}^{n} \,a_{i}\cdot x^{i}, where n is the order of the polynomial. The example has the following information:

n = 3, a_{0} = 17, a_{1} = -6, a_{2} = 2, a_{3} = 5.

b) The closure property means that polynomials must be closed with respect to addition and multiplication, which is demonstrated hereafter:

Closure with respect to addition:

Let consider polynomials p_{1} and p_{2} such that:

p_{1} = \Sigma \limits_{i=0}^{m} \,a_{i}\cdot x^{i} and p_{2} = \Sigma \limits_{i=0}^{n}\,b_{i}\cdot x^{i}, where m \geq n

p_{1}+p_{2} = \Sigma \limits_{i=0}^{n}\,(a_{i}+b_{i})\cdot x^{i} + \Sigma_{i=n+1}^{m}\,a_{i} \cdot x^{i}

Hence, polynomials are closed with respect to addition.

Closure with respect to multiplication:

Let be p_{1} a polynomial such that:

p_{1} = \Sigma \limits_{i=0}^{m} \,a_{i}\cdot x^{i}

And \alpha an scalar. If the polynomial is multiplied by the scalar number, then:

\alpha \cdot p_{1} = \alpha \cdot \Sigma \limits_{i = 0}^{m}\,a_{i}\cdot x^{i}

Lastly, the following expression is constructed by distributive property:

\alpha \cdot p_{1} = \Sigma \limits_{i=0}^{m}\,(\alpha\cdot a_{i})\cdot x^{i}

Hence, polynomials are closed with respect to multiplication.

4 0
3 years ago
Find the value of x
Vilka [71]
<span>An exterior angle of a triangle is equal to the sum of the opposite interior
angles  </span>⇒  x = 30 + 90 = 120°
6 0
3 years ago
How did business leaders in the late nineteenth century utilize vertical integration? a. They maintained control of the raw mate
bulgar [2K]

Business leaders in the late nineteenth century utilized vertical integration by maintaining control of production and distribution of their products.

Answer: Option C

<u>Explanation: </u>

Vertical integration is a competitive strategy that gives the company full control over one or more stages of product production or distribution. Rockefeller tirelessly tried to take full control of business 'oil refinery'. While other business people were flooding the area in search of quick fortune, Rockefeller was thinking of destroying his rivals and creating a real monopoly in the refining industry.

Looking for even more control, Rockefeller saw the benefits of organizing the transportation to his products. Then, he began to develop his business through vertical integration, in which the company analyses all aspects of the product life cycle, from raw material extraction, through the production process, to the final delivery of the product.

Other industrialists quickly followed, including Gustavus Swift, who at the end of the 19th century used vertical integration to dominate the American meat packaging industry.

3 0
3 years ago
A 2-column table has 4 rows. The first column is labeled x with entries negative 4, negative 2, 3, 3. The second column is label
Burka [1]

Answer:

y ≤ –2x + 3

Step-by-step explanation: i got it right on edge 2020

5 0
3 years ago
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